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Dmitrij [34]
3 years ago
7

What’s the divisible of 54 and 3

Mathematics
2 answers:
aleksley [76]3 years ago
5 0
18 is the answer
. Divide by 3
UkoKoshka [18]3 years ago
4 0
Fifteen divided by three is 18
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PLEASE HELP! Determine the slope and the y-intercept of the table.
natita [175]

Let's take the first 2 x and y values and use them. First, you need to fill in your formula: y2-y1/x2-x1. It should look like this: 5-2/4-2. Then solve and you should get 3/2. You can't simplify it. So, this is your slope.

Next, you need to put this is into another formula. The formula is y-y1=m(x-x1). Take the first coordinate pair and plug it in for x1 and y1. Plug in your slope for m. When it's filled in, you should have y-2+3/2(x-1). It's hard to explain how to solve it so i'll just write it out.

y-2=3/2(x-2)

y-2=3/2x-3

y=3/2x-1

So, we have our equation in slope intercept form so that we have our slope and our y-intercept.

Y-intercept: -1

Slope: 3/2

Please put this as brainliest it took awhile and I hope this helped :) reply with questions if you still need help or have questions about the steps

3 0
2 years ago
PLS HELP 30 POINTS PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS HELP PLS
svp [43]

Answer:

it's quite difficult

Step-by-step explanation:

I think it will...

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%282x%2B1%29%28x-5%29%7D%7B%28x-5%29%28x%2B4%29%5E%7B2%7D%20%7D" id
dybincka [34]

i) The given function is

f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}

The domain is

(x-5)(x+4)^2\ne 0

(x-5)\ne0,(x+4)^2\ne 0

x\ne5,x\ne -4

ii) For vertical asymptotes, we simplify the function to get;

f(x)=\frac{(2x+1)}{(x+4)^2}

The vertical asymptote occurs at

(x+4)^2=0

x=-4

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

2x+1=0

2x=-1

x=-\frac{1}{2}

iv) To find the y-intercept, we substitute x=0 into the reduced fraction.

f(0)=\frac{(2(0)+1)}{(0+4)^2}

f(0)=\frac{(1)}{(4)^2}

f(0)=\frac{1}{16}

v) The horizontal asymptote is given by;

lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0

The horizontal asymptote is y=0.

vi) The function has a hole at x-5=0.

Thus at x=5.

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

6 0
2 years ago
I have no clue what it is
Orlov [11]
13.95+2.25+2.25+2.25+2.75+2.75+2.75= 28.95

6 0
2 years ago
What’s this ????????
Dafna11 [192]

Answer:

w^6/9

Step-by-step explanation:

3^-2/w^-6

w^6/9

7 0
3 years ago
Read 2 more answers
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