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Irina18 [472]
3 years ago
10

You randomly choose one of the following numbers shown. Find the probability the event can occur choosing a number greater than

4. (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11)
Mathematics
1 answer:
sergey [27]3 years ago
7 0
<h3>Answer:  7/11</h3>

======================================================

Explanation:

The event space is the set of outcomes we want to happen.

The event space is {5, 6, 7, 8, 9, 10, 11} which consists of getting a value greater than 4. There are 7 items in this event space. Let A = 7.

The sample space consists of all possible outcomes. The sample space is {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11} and there are 11 items in the sample space. Let B = 11.

Divide the values of A and B to get the answer we're after

A/B = 7/11

This is the probability of selecting a value greater than 4.

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For which value of X is the row in the table of values incorrect? The function is the quadratic function Y=3/4x^2
svet-max [94.6K]

Answer:

The row with x = 2 and y = 4 is incorrect. The y value should be y = 3 when x = 2.

==============================================================

Explanation:

Fractions can be a bit of a pain, so I'm going to be converting to decimal form to help with the computation; however, I will convert the y value results to mix number form so that it matches what the table shows.

Keep in mind that 3/4 = 0.75 when you use a calculator or long division. So a number like 2.75 means 2 & 3/4 (two and three quarters)

---------------

Let's check the first row. Plug in x = 0 and it leads to...

y = (3/4)*x^2

y = (3/4)*0^2

y = (3/4)*0

y = 0.75*0

y = 0

This shows us that row 1 is correct. When x = 0, y = 0 leading to (x,y) = (0,0).

-------------

Repeat the same basic outline of steps, but now use x = 2

y = (3/4)*x^2

y = (3/4)*2^2

y = (3/4)*4

y = 0.75*4

y = 3

So instead of 4, the proper y value is y = 3 when x = 2. This means row 2 is the answer (the row that has the incorrect values).

-------------

For the sake of completeness, let's see if the third row is correct or not. Plug in x = 3

y = (3/4)*x^2

y = (3/4)*3^2

y = (3/4)*9

y = 0.75*9

y = 6.75

y = 6 & 3/4

We see that x = 3 points to y = 6 & 3/4, so we have the correct values in this row. We can cross this off the list of choices.

-------------

Finally, let's check x = 5

y = (3/4)*x^2

y = (3/4)*5^2

y = (3/4)*25

y = 0.75*25

y = 18.75

y = 18 & 3/4

We get the proper y value. So we can also cross this off the list.


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3 years ago
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Answer:

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Step-by-step explanation:

y + 4 = 3(x - 9)

y + 4 = 3x - 27

y = 3x - 23

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