The answer would be<span>27 * 3/2 = 40.5</span>
<u>2q</u>
Answer:
solution given:
now
by using property of logarithms
now
=2q
since
Step-by-step explanation:
Answer: <em>1=60°</em>
Step-by-step explanation:
<em>First, let's take our given angle of 30°</em>
<em>30° is in a right triangle, so the angles must be 90°, 60°, and 30°</em>
<em>Now the angle that is 45° makes angle 1 congruent to angle 60°</em>
<em>Meaning angle 1 is </em><em>60°</em>
Answer: 576 cm³
Explanation:
Radius = Diamater ÷ 2 = 8 ÷ 2 = 4 cm
V = π r² h = 3 (4)² (12) = 576 cm³
Answer:
(1-cos2A) /(1+cos2A) =tan²A
Proof:
We know that,
cos(A+B) =cosA.cosB-sinA.sinB
=>cos2A=cos(A+A)
=>cos2A=cosA.cosA - sinA.sinA
=>cos2A=cos²A-sin²A
=>cos2A=(cos²A-sin²A)/(cos²A+sin²A
Since {cos²A+sin²A=1}
Divide the numerator & the denominator by (cos²A) to get,
cos2A = {(cos²A-sin²A) ÷cos²A} / {(cos²A+sin²A) ÷cos²A}
cos2A ={(1-tan²A)/(1+tan²A)}
Then,
1-cos2A = 1-[{(1–tan²A)/(1+tan²A)}]
1-cos2A =(1+tan²A-1+tan²A)/(1+tan²A)
1-cos2A=(2tan²A)/(1+tan²A)
And now.......
1+cos2A=1+[{(1-tan²A)/(1+tan²A)}]
1+cos2A={1+tan²A+1-tan²A}/{1+tan²A}
1+cos2A=2/(1+tan²A)
So now,
(1-cos2A)/(1+cos2A)= {2tan²A/(1+tan²A)}÷{2/(1+tan²A)}
={(2tan²A)(1+tan²A)}÷{2(1+tan²A)}
=tan²A
Step-by-step explanation:
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