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mihalych1998 [28]

3 years ago

7

Algebra help - please be so kind - god bless. 2&3 please

1 answer:

azamat3 years ago

4 0

2. -11 sq rt of 112
Sq rt of 16 times sq rt of 7
Becomes 4 sq rt of 7
Multiply -11 times 4 sq rt of 7
-44 sq rt of 7
Answer A

3. Subtract 17-9 since they are hitch the same sq rt

Answer 8 sq rt of 17

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solmaris [256]

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3 years ago

Claire cut some apples into eighths. She and her friends ate all but 17 pieces. How many whole apples and parts of apples did sh

Fiesta28 [93]

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7 0

3 years ago

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The width of a rectangle is 30% of its length what is the area of the rectangle. when the length is 40ft.

zaharov [31]

Answer:

480ft squared

Step-by-step explanation:

length= 40*0.30= 12

area= length×width

area=40×12

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3 years ago

s344n2d4d5 [400]

Expanded Notation:

A. 654.362 = (6x100) + (5x10) + (4x1) + (3x0.1) + (6x0.01) + (2x0.001)

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3 years ago

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Can someone give me the answers and step by step instructions please??

professor190 [17]

Answer:

$-1,4,-7,10,...$ neither

$192,24,3,\frac{3}{8},...$ geometric progression

$-25,-18,-11,-4,...$ arithmetic progression

Step-by-step explanation:

Given:

sequences: $-1,4,-7,10,...$

$192,24,3,\frac{3}{8},...$

$-25,-18,-11,-4,...$

To find: which of the given sequence forms arithmetic progression, geometric progression or neither of them

Solution:

A sequence forms an arithmetic progression if difference between terms remain same.

A sequence forms a geometric progression if ratio of the consecutive terms is same.

For $-1,4,-7,10,...$ :

$4-(-1)=5\\-7-4=-11\\10-(-7)=17\\So,\,\,4-(-1)\neq -7-4\neq 10-(-7)$

Hence,the given sequence does not form an arithmetic progression.

$\frac{4}{-1}=-4\\\frac{-7}{4}=\frac{-7}{4}\\\frac{10}{-7}=\frac{-10}{7}\\So,\,\,\frac{4}{-1}\neq \frac{-7}{4}\neq \frac{10}{-7}$

Hence,the given sequence does not form a geometric progression.

So, $-1,4,-7,10,...$ is neither an arithmetic progression nor a geometric progression.

For $192,24,3,\frac{3}{8},...$ :

$\frac{24}{192}=\frac{1}{8}\\\frac{3}{24}=\frac{1}{8}\\\frac{\frac{3}{8}}{3}=\frac{1}{8}\\So,\,\,\frac{24}{192}=\frac{3}{24}=\frac{\frac{3}{8}}{3}$

As ratio of the consecutive terms is same, the sequence forms a geometric progression.

For $-25,-18,-11,-4,...$ :

$-18-(-25)=-18+25=7\\-11-(-18)=-11+18=7\\-4-(-11)=-4+11=7\\So,\,\,-18-(-25)=-11-(-18)=-4-(-11)$

As the difference between the consecutive terms is the same, the sequence forms an arithmetic progression.

3 0

3 years ago