What is 54t x 65f please help me on this question

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

laiz [17]

Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of $(h\circ g)(-6)$ is 2401.

7 0

3 years ago

3. Put these in order from greatest to least.

Masja [62]

3. 333, 330, 330, 303, 30, 30, 30, 030, 003

4. I’m don’t get what your asking for this

5 0

4 years ago

Erica makes $2850 per month in salary selling used cars. She sold $125,000 worth of cars last month. If she gets paid a 4% commi

Roman55 [17]

UwU 100 plus another

3 0

3 years ago

Name

juin [17]

Answer:

35:4 is the ratio.

Step-by-step explanation:

The students are written on the top of the fraction because of the wording students to teacher.

8 0

3 years ago

Determine each of the following.

castortr0y [4]

Answer:

(a) $\{1,2,3,4,5,6,7,8,9,10\}$

(b) 10

(c) $\{\}$

(d) 0

(e) 1024

Step-by-step explanation:

(a)

A = {x ∈ Z | 0 < x, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

$0$ ... (1)

$x^2\leq 100$

Taking square root on both sides.

$-\sqrt{100}\leq x\leq \sqrt{100}$

$-10\leq x\leq 10$ .... (2)

Using (1) and (2) we get

$0$

Since x ∈ Z,

$A=\{1,2,3,4,5,6,7,8,9,10\}$

(b)

We need to find the value of | {x ∈ Z | 0 < x, x² ≤ 100}| or |A|. It means have to find the number of elements in set A.

$|A|=10$

| {x ∈ Z | 0 < x, x² ≤ 100}| = 10

(c)

B = {x ∈ Z | x > 10, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

$x>10$ ... (3)

$x^2\leq 100$

It means

$-10\leq x\leq 10$ .... (4)

Inequality (3) and (4) have no common solution, so B is null set or empty set.

$B=\{\}$

(d)

We need to find the value of |{x ∈ Z | x > 10, x² ≤ 100}| or |B|. It means have to find the number of elements in set B.

$|B|=0$

|{x ∈ Z | x > 10, x² ≤ 100}| = 0

(e)

We need to find the value of | P(A) |. P(A) is the power set of set A.

Number of elements of a power set is

$N=2^n$

where, n is the number of elements of set A.

We know that the number of elements of set is 10. So the value of |P(A)| is

$|P(A)|=2^{10}$

$|P(A)|=1024$

Therefore |P(A)|=1024.

7 0

3 years ago