we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A
--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)
therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
Answer:
1013500000
Step-by-step explanation:
Addition, mate.
Answer:
1/221=0.0045
Step-by-step explanation:
Answer:
y= -7
Step-by-step explanation:
y=ax+b
Find a where a=y2-y1 /x2-x1
y2=13,y1=5 x2=5,x1=3
substituting the values
a=13-5/5-2
a=8/2
a=4
substituting a into the formular
y=4x+b
taking x and y values let say 3 and 5 for x and y
the equation becomes
5=4(3)+b
5=12+b
5-12=b
-7=b
substituting the values of a and b into the equation
y=4x-7
when x=0
y=4(0)-7
y=0-7
y=-7
so when x=0,y=-7
4 [ 5 (12 + 3) - 2 ] - 7
4 [ 5 (15) - 2 ] - 7
4 [ 75 - 2 ] - 7
4 [ 73 ] - 7
292 - 7
285
