3 years ago

What is 8x cubed y to the second power -7x squared y + 8x+4 -6x cubed y squared + 2x squared y + 4x squared y -3x +5

1 answer:

5 0

The answer is (-1,7)

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Leokris [45]

The answers are:

Diameter: 30m
Circumference: 94.24777960769379
Area: 706.8583470577 m2

I hope this helps you. Good luck with your work!

6 0

3 years ago

lina2011 [118]

3 to the power of 1 simplified, is just 3.

7 0

3 years ago

tatiyna

cos $\alpha=\frac{adjacent}{hypotenuse}$

cosC = $\frac{45}{51}$

4 0

3 years ago

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

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3 years ago

Phoenix [80]

47 is 0.47 and 2/3 is 0.66

4 0

3 years ago