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Natali [406]
3 years ago
13

Have any idea on this question ?

Mathematics
1 answer:
rewona [7]3 years ago
8 0
The answer is D just trust me 
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Divide 54 into two parts so that four times the greater equals five time the less​
LUCKY_DIMON [66]
Let the both the parts be 'x' and 'y'
x>y
We know that 4x = 5y
so x = 5y/4
x + y = 54
Replacing x we get
(5y/4) + y = 54
(5y +4y)/4 = 54
9y = 216
y = 24
Replacing y in ' x+y = 54'
we get x = 30

Hence the larger part is 30 whereas the smaller part is 24
5 0
3 years ago
Consider these three numbers expressed in scientific notation 2.4 x10^4 , 6.3 x10^5 , and 9.6 x10^7
____ [38]
I considered them, but if you wanted them evaluated, here you go
24,000
630,000
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8 0
3 years ago
What is the result of subtracting the second equation from the first?<br> -4x-2y=-2<br> x-2y=9
TEA [102]

Answer:

x = 11/5 or 2 1/5

Step-by-step explanation:

propagate the negative through the bottom equation

-5x = -11

x = 11/5

3 0
3 years ago
Given sin theta= 6/11 and sec theta &lt; 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
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Estimate the answers to 943.18 + 103.89 by first rounding each number to the nearest ten
kondaur [170]
943.18 + 103.89 = 1040
3 0
3 years ago
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