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monitta
3 years ago
13

Select all of the expressions that have a value of 18

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

(a)\ 324 \div 18; (b)\ 468 \div 26 and (d)\ 1062 \div 59

Step-by-step explanation:

Required

Select which expression equals 18

(a)\ 324 \div 18

This gives:

324 \div 18 - 18

(b)\ 468 \div 26

This gives:

468 \div 26 = 18

(c)\ 724 \div 10

This gives:

724 \div 10 = 72.4

(d)\ 1062 \div 59

This gives:

1062 \div 59 = 18

(e)\ 51071 \div 60

This gives:

51071 \div 60 = 851.182

From the above computations:

(a)\ 324 \div 18; (b)\ 468 \div 26 and (d)\ 1062 \div 59 are equivalents of 18

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Step-by-step explanation:

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3 years ago
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Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

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3 years ago
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