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shtirl [24]
3 years ago
6

What is the equation process to this question?

Mathematics
1 answer:
Andreyy893 years ago
5 0

The given equation is h(t)=-16t^2+80t+4 where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation h(t)=-16t^2+80t+4, we get;

h(2)=-16(2)^2+80(2)+4

Simplifying the terms, we get;

h(2)=-64+160+4

h(2)=100

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation h(t)=-16t^2+80t+4, we get;

h(4)=-16(4)^2+80(4)+4

Simplifying the terms, we get;

h(4)=-256+320+4

h(4)=68

Thus, the height of the ball after 4 seconds is 68 feet.

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SOLUTION:

Step 1:

From the given question, and comparing the scores in classes A and B

Step 2:

Question one, to know the class which had the better overall result on the exam;

(I) The scores in class A ranges from 65 to 100, while that of class B ranges from 60 to 90. This explains that class A had better results.

(ii) The median of the scores in class A is 85, while the median of the scores in class B is 75, this is another piece of supporting evidence that class A had better results.

Step 3:

Question two, to know the class which had greater variability in the results;

For a better understanding of this question, I need to explain the concept of variability in statistics.

Variability in statistics refers to the difference being exhibited by data points within a data set, as related to each other or as related to the mean. This can be expressed through the range, variance or standard deviation of a data set.

Step 4:

So we need to find the range of scores in each of the two classes and then compare, the class with the greater range has the greater variability.

The Range is the difference between the lowest and highest score (H - L), where H is the highest score and L is the lowest score.

Step 5:

Applying the formula for range stated in step 4;

For Class A; H = 100 and L = 65

For Class B; H = 90 and L = 60

The range for class A; H - L = 100 - 65 = 35

The range for class B; H - L = 90 - 60 = 30

By comparing the range of class A and that of B, it is clear that Class A had a greater range (variability)

CONCLUSION:

Class A had better overall results in the exam and greater variability in the results.

6 0
10 months ago
Does this set of ordered pairs represent a function? Why or why not? {(–1, 5), (0,-3), (2,7), (4,0), (7, 5)}
Kisachek [45]
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8 0
3 years ago
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Fraction Questions:
bagirrra123 [75]

Answer:

0

Step-by-step explanation:

3 0
2 years ago
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Can you guys please help me?! it’s due tomorrow and i don’t know the answers :(
Vlada [557]

Answer:

I think it is the second one because -4 is the least

Step-by-step explanation:

4 0
3 years ago
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