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shtirl [24]
3 years ago
6

What is the equation process to this question?

Mathematics
1 answer:
Andreyy893 years ago
5 0

The given equation is h(t)=-16t^2+80t+4 where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation h(t)=-16t^2+80t+4, we get;

h(2)=-16(2)^2+80(2)+4

Simplifying the terms, we get;

h(2)=-64+160+4

h(2)=100

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation h(t)=-16t^2+80t+4, we get;

h(4)=-16(4)^2+80(4)+4

Simplifying the terms, we get;

h(4)=-256+320+4

h(4)=68

Thus, the height of the ball after 4 seconds is 68 feet.

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-12x + 12 = 4 - 15x + 9
emmainna [20.7K]

Answer:

x = 1/3

Step-by-step explanation:

-12x + 12 = 4 - 15x + 9

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