An obtuse angle is an angle that is in between 90 degrees and 180 degrees. It looks like this
Answer:
Option c
or 
Step-by-step explanation:
The absolute value is a function that transforms any value x into a positive number.
Therefore, for the function
x> 0 for all real numbers.
Then the inequation:
has two cases
if
(i)
if
(ii)
We solve the case (i)

We solve the case (ii)

Then the solution is:
or 
Answer:
it is a because you subtract the ten from both side and that makes the -8 into a -18 then you divide by 3 and your answer is -6
Answer:
inequality form -2<x<5
interval notation (-2,5)
sure of my answer
−Step-by-step explanation:
Answer:

Step-by-step explanation:
This problem can be solved using the pythagorian theoreme:

Where:



We isolate our incognita an we get:

We supplant with the given data:




