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expeople1 [14]
3 years ago
12

How many possible midsegments are there for any quadrilateral?

Mathematics
1 answer:
Furkat [3]3 years ago
3 0
Its can have 3 midsegments
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What is the sum of 171
Y_Kistochka [10]
Divide 171 by 3. 57
Therefore the middle integer is 57 
<span>Therefore the highest integer is "2" higher = 59 </span>
<span>The lowest integer is 2 lower to "balance" the higher digit = 55 </span>

<span>Therefore using common sense rather than "let x=....." the answer is 55, 57 and 59.</span>
3 0
3 years ago
What is the greatest whole number that can be multiplied by 7 to result in a product that is less than 100,000?
Scilla [17]
  1. 100000  \times 7 =
4 0
4 years ago
2 1 point
mafiozo [28]

Answer:

  • The graph has a minimum.
  • The graph has a y-intercept at (0, -3).
  • The solutions ... are -1 and 3.
  • The vertex is located at (1, -4).
  • In the equation, 'a' would be positive.

Step-by-step explanation:

When the graph has a low point, it has a minimum. 'a' is positive in that case. The coordinates of that low point are (1, -4). That point is the vertex.

The graph crosses the y-axis at y = -3, so the y-intercept is (0, -3).

The graph crosses the x-axis at (-1, 0) and (3, 0). These points represent the solution to the equation y = 0.

  • The graph has a minimum.
  • The graph has a y-intercept at (0, -3).
  • The solutions ... are -1 and 3.
  • The vertex is located at (1, -4).
  • In the equation, 'a' would be positive.
5 0
3 years ago
Solve the triangle.
saw5 [17]

Answer:

Step-by-step explanation:

because <u>c</u> is shorter than<u> a</u> we know C is a smaller angle than A

so the first choice is out.

use the law of cosines to find b

b^{2} = a^{2} +c^{2} -2*a*c*cos(B)

b^{2} =1681+400-1326.787871

b^{2}= 754.21219

b= \sqrt{754.21219}

b= 27.46292

so the last choice looks good

5 0
3 years ago
Lenore has 1/4 Cup of candy,she divides the candy among her 2 friends. How much. Candy will each friend get?
Nesterboy [21]
Each friend will get 1/8
4 0
3 years ago
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