A = .5 r^2 theta
Theta must be in radians
A = .5 (15.7)^2 (102)(pi/180)
A= 219 mm^2
Answer:
<h2>w= 0.83 N</h2>
Step-by-step explanation:
The column has the shape of a cylinder hence the formula for the volume of a cylinder is

Given
diameter d= 390 mm
radius r= 390/2= 195 mm to meter = 0.195 m
length or height h= 3 m
applying the data to the formula we have

we can now use the volume in addition with the density given to solve for the mass using the expression for density
density= mass/volume
2.45= mass/0.035
mass= 2.45*0.035
mass= 0.085 mg
We know that weight
w= mass* acceleration
w= 0.085*9.81
w= 0.83 N
9514 1404 393
Answer:
see attached
Step-by-step explanation:
Usually, a one-variable solution set is graphed on a number line. However, since you asked for it, the attachment shows it graphed on the coordinate plane.
Given:
The function that represents how the amount of fuel changes as a function of distance flown is

where x represents miles flown, and f(x) represents the amount of fuel remaining.
To find:
The rate of change for this scenario.
Solution:
The slope intercept form of a linear function is
...(i)
Where, m is the slope or rate of change and b is the y-intercept.
We have,
...(ii)
On comparing (i) and (ii), we get

Therefore, the rate of change for this scenario is -0.9. It means, the amount of fuel in the airplane is decreasing by 0.9 gallons per mile.
B) 0.28
arcsin(.28)=x
x=16.3
cos(90-16.3) = 0.28