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3 years ago

A formula to find the frequency, f, of a cyclic phenomena based on the period, T, is

Mathematics

1 answer:

jarptica [38.1K]3 years ago

8 0

Step-by-step explanation:

The frequency and the time period is related by the formula as follows :

$f=\dfrac{1}{T}$

Here, f is frequency and T is time period

Now, we need to solve T in terms of f.

Firstly, cross multiplying the above equation,

$f\times T=1$

Now dividing both sides by T.

$\dfrac{f\times T}{T}=\dfrac{1}{T}\\\\f=\dfrac{1}{T}$

Hence, this is the required solution.

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When p = 12, t = 2, and s = 1/6, r = 18. If r varies directly with p and inversely with the product of s and t, what is the cons

Ilia_Sergeevich [38]

R = kp/st
18 = 12k/(1/6 x 2)
18 = 12k/(1/3)
18 = 36k
k = 18/36 = 1/2

3 0

3 years ago

2. The following triangle, ∆, has angle measures as shown.

klio [65]

Answer:

x=29. Angle C= 93

Step-by-step explanation:

3(x+2)= 3x+6.

3x+6+52+35= 3x+93.

180-93=87.

87/3= 29. So that means x=29.

for proof you can do 3(29)+93 and you'll get 180.

For angle C; 3(29+2)= 3x31. 31x3= 93.

Angle C= 93 degrees.

6 0

3 years ago

A 1.0 l buffer solution is 0.15 m in hcn and 0.10 m in nacn. which action will destroy the buffer?

rjkz [21]

The buffer will probably be destroyed by the addition of HCN.

<h3>What is buffer solution?</h3>

A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.

Given that a 1.0 l buffer solution is 0.15 m in HCN and 0.10 m in NaCN.

We need to find a action which one destroy the buffer solution.

A buffer is a substance made of salt and a weak acid that is beneficial. From the aforementioned chemicals, HCN is a potent acid and NaCN is a salt between HF and NaCN. Therefore, the buffer will probably be destroyed by the addition of HCN.

To learn more about buffer solution from the given link

brainly.com/question/22390063

#SPJ4

8 0

2 years ago

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of

Umnica [9.8K]

$\large\bold{{Question :}}$

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

$\large\bold\red{\underline{Solution :-}}$

Here, O is the center of the circle.

⟼ Given :

OQ = 25 cm
PQ = 24 cm

⟼ To Find : We have to find the radius OP.

Since QP is tangent, OP perpendicular to QP.

(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)

So, ∠OPQ=90°

⟼ By Applying Pythagoras Theorem :

OP² + RQ² = OQ²

OP² + (24)² = (25)²

OP² = 625 - 576

OP² = 49

OP = √49

OP = 7 cm

Hence, The Radius is 7 cm

⠀⠀

⠀

<h3>-MissAbhi</h3>

7 0

2 years ago

Read 2 more answers

State the size of angle OAB, giving a reason for your answer

lina2011 [118]

Answer:

OAB is 90°

Explanation -

Given - A circle with centre O

According to the theorem , The tangent of a circle and the line of tangency make an angle of 90°

5 0

3 years ago