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Sati [7]
2 years ago
12

1

Mathematics
1 answer:
hodyreva [135]2 years ago
7 0

Using the given box and whisker plot, it is found that the mean most likely exceeds the median for Elaine, hence option B is correct.

<h3>What does a box and whisker plot shows?</h3>

A box and whisker plot shows three things:

  • The 25th percentile, which is the median of the bottom 50%.
  • The median.
  • The 75th percentile, which is the median of the upper 50%.

In this problem:

  • The plot for Sarah is right-skewed, due to the proximity of the 25th percentile and the median. In a right skewed plot, the mean is less than the median.
  • For Elaine, it is left-skewed, due to the proximity of the median to the 75th percentile. In a left skewed plot, the mean exceeds the median.

The mean most likely exceeds the median for Elaine, hence option B is correct.

More can be learned about box and whisker plots at brainly.com/question/27743205

#SPJ1

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Determina la masa molar y el volumen que ocupa la siguiente sustancia CO2, si su masa es de 28 gr. *
balandron [24]

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

7 0
3 years ago
What is the solution to the system of equations y23x3 x 2
bija089 [108]

The Solution for the given system of equations is (-2) and (\frac{5}{3}).

The given are linear equations as follow:
y = \frac{2}{3}x + 3              .. ... ...(1)
and x  = -2.          .. .... ...(2)

We already know the first part of the solution (x) which is -2.  We can find the other part (y) by putting the value of equation (2) in equation (1).

By putting the values of x in equation (1), we get

y = (\frac{2}{3})(-2) + 3
y = \frac{-4}{3} + 3

Taking the L. C. M of denominators which will be '3', we get:

y = \frac{-4 + 9}{3}

y = \frac{5}{3}

So the second part (y) of the solution of the given equation is \frac{5}{3}.

Hence, the overall solution to the given system of equation is (-2, \frac{5}{3}).

To learn more about the System of equations, click here

brainly.com/question/26218294

#SPJ4

8 0
1 year ago
The same player is going to play the game 200 times consecutively. How many black balls should he expect to pick
DerKrebs [107]

Answer:

200

Step-by-step explanation:

It is given that the same player is going to play a game one after another continuously about 200 times. During the game the player is going to pick up  black color balls.

If the player picks at least one black color ball at one time of the game, therefore, the probability of the number of black balls that the player is going to pick is 200 balls.

8 0
3 years ago
You are planning to email to two lists. the first list has 1,200 names. the second list has 900 names. there are 150 names that
Snezhnost [94]

Answer:  There are 1800 unique names from both the lists.

Explanation:

Since we have given that

there are two lists :

In First list, number of names = 1200

In Second list, number of names = 900

According to question , we have also given that

there are 150 names that appear on both lists,

So,

Number of unique names in the first list  is given by

1200-150=1050

Number of unique names in the second list is given by

900-150=750

Therefore, total number of unique names is given by

1050+750=1800

Hence, there are 1800 unique names from both the lists.

3 0
3 years ago
Read 2 more answers
2x-5y+5z=-10<br> 5x-4y+3z=-19<br> X-y+5z=17
yarga [219]

Answer:

x = -125/71 , y = 448/71 , z = 356/71

Step-by-step explanation:

Solve the following system:

{2 x - 5 y + 5 z = -10 | (equation 1)

5 x - 4 y + 3 z = -19 | (equation 2)

x - y + 5 z = 17 | (equation 3)

Swap equation 1 with equation 2:

{5 x - 4 y + 3 z = -19 | (equation 1)

2 x - 5 y + 5 z = -10 | (equation 2)

x - y + 5 z = 17 | (equation 3)

Subtract 2/5 × (equation 1) from equation 2:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - (17 y)/5 + (19 z)/5 = (-12)/5 | (equation 2)

x - y + 5 z = 17 | (equation 3)

Multiply equation 2 by 5:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y + 19 z = -12 | (equation 2)

x - y + 5 z = 17 | (equation 3)

Subtract 1/5 × (equation 1) from equation 3:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y + 19 z = -12 | (equation 2)

0 x - y/5 + (22 z)/5 = 104/5 | (equation 3)

Multiply equation 3 by 5:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y + 19 z = -12 | (equation 2)

0 x - y + 22 z = 104 | (equation 3)

Subtract 1/17 × (equation 2) from equation 3:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y + 19 z = -12 | (equation 2)

0 x+0 y+(355 z)/17 = 1780/17 | (equation 3)

Multiply equation 3 by 17/5:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y + 19 z = -12 | (equation 2)

0 x+0 y+71 z = 356 | (equation 3)

Divide equation 3 by 71:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y + 19 z = -12 | (equation 2)

0 x+0 y+z = 356/71 | (equation 3)

Subtract 19 × (equation 3) from equation 2:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x - 17 y+0 z = (-7616)/71 | (equation 2)

0 x+0 y+z = 356/71 | (equation 3)

Divide equation 2 by -17:

{5 x - 4 y + 3 z = -19 | (equation 1)

0 x+y+0 z = 448/71 | (equation 2)

0 x+0 y+z = 356/71 | (equation 3)

Add 4 × (equation 2) to equation 1:

{5 x + 0 y+3 z = 443/71 | (equation 1)

0 x+y+0 z = 448/71 | (equation 2)

0 x+0 y+z = 356/71 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{5 x+0 y+0 z = (-625)/71 | (equation 1)

0 x+y+0 z = 448/71 | (equation 2)

0 x+0 y+z = 356/71 | (equation 3)

Divide equation 1 by 5:

{x+0 y+0 z = (-125)/71 | (equation 1)

0 x+y+0 z = 448/71 | (equation 2)

0 x+0 y+z = 356/71 | (equation 3)

Collect results:

Answer: {x = -125/71 , y = 448/71 , z = 356/71

5 0
4 years ago
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