All categories

3 years ago

7,423.28 fraction form

Mathematics

2 answers:

cestrela7 [59]3 years ago

6 0

7,423.28 / 1,000.00

1,000.00 is like 100 percent, while 7,423.28 rounded is SORT OF like 74 percent (74.2328)

Ahat [919]3 years ago

3 0

185582/25

or

7423 7/25
I hope that helps

You might be interested in

What is the correct answer to this question? 13M=7.15

ad-work [718]

Answer:

m=0.55

Step-by-step explanation:

Divide each term by 13 and simplify.

7 0

3 years ago

Read 2 more answers

Find the value of the determinant. 4 8 10 4 0-1 3 - 2 4

VLD [36.1K]

Answer:

- 240

Step-by-step explanation:

We have to find the value of the following determinant

$\left|\begin{array}{ccc}4&8&10\\4&0&-1\\3&-2&4\end{array}\right|$

Now, we know that the value of a general determinant $\left|\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right|$ is given by [a( ei - fh) + b(fg - di) + c(dh - eg)]

Therefore, the value of the given determinant is

= 4[0 × 4 - (-1)(-2)] + 8[3(-1) - 4 × 4] + 10[4(-2) - 3 × 0]

= - 8 - 152 - 80 = - 240 (Answer)

4 0

4 years ago

Advance pile up trigonometry

earnstyle [38]

Answer:

x = 6.9168 or x = 7

Step-by-step explanation:

Hope that helps :)

3 0

3 years ago

A complex number, represented by z = x + iy, may also be visualized as a 2 by 2 matrix

Marat540 [252]

Answer:

Step-by-step explanation:

A) Suppose that we have the complex numbers

$z= x + iy \quad \text{and} \quad \\\\ \tilde{z}=\tilde{x} + i \tilde{y}$

Remember that to sum complex numbers, we sum the real parts of the two numbers to get the real part and the imaginary parts of the two numbers to get the imaginary part. Hence,

$z+\tilde{z} = (x + i y) + (\tilde{x} + i \tilde{y}) = (x + \tilde{x})+i (y+\tilde{y})$

On the other hand, if we sum the matrix visualizations of $z \quad \text{and} \quad \tilde{z}$ we get

$\left[\begin{array}{cc}x &y\\-y&x\end{array}\right] + \left[\begin{array}{cc}\tilde{x}&\tilde{y}\\ -\tilde{y}&\tilde{x}\end{array}\right] = \left[\begin{array}{cc}x + \tilde{x}& y + \tilde{y}\\-(y+\tilde{y})&x+\tilde{x}\end{array}\right]$

which is the matrix visualization of $z + \tilde{z}$ .

To multiply two complex numbers, we use the distributive law to multiplly and then separete the real part from the imaginary part

$z \cdot \tilde{z}= (x + iy) \cdot (\tilde{x} + i \tilde{y})=(x \tilde{x} + i x \tilde{y} + i \tilde{x} y - y\tilde{y} ) = (x\tilde{x}-y\yilde{y})+i(x\tilde{y}+\tilde{x}y)$

Again, if we multiply the matrix visualizations of $z \quad \text{and} \quad \tilde{z}$ we get

$\left[\begin{array}{cc}x&y\\-y&x\end{array}\right]\left[\begin{array}{cc}\tilde{x}&\tilde{y}\\-\tilde{y}&\tilde{x}\end{array}\right] = \left[\begin{array}{cc}x\tilde{x}-y\tilde{y}&x\tilde{y}+y\tilde{x}\\-y\tilde{x}-x\tilde{y}&x\tilde{x}-y\tilde{y}\end{array}\right]$

which is the matrix viasualization of $z\cdot\tilde{z}.$

B) Since the usual matrix operations are consisten with the usual addition and multiplication rules in the complex numbers, we can use them to find the multiplicative inverses of a complex number $z=x+iy$ .