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iragen [17]
3 years ago
10

Is this equation proportional y= 3x? why or why not?

Mathematics
1 answer:
eduard3 years ago
5 0

Step-by-step explanation:

a variable cannot equal another variable

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Cathy conducted an experimentin which she placed red, yellow, blue, and orange pieces of paper in a hat and drew them out withou
Allisa [31]

Answer:

28/55

Step-by-step explanation:

First thing you do is add up all of the data values.

This is the total of everything you can draw.

in this case it would by 55.

We set this as the denominator and set the numerator to the ammount of times orange has been drawn.

This would result in our answer.

Hope this helps!

4 0
3 years ago
Sally is filling glass containers in the shape of cylinders with different colors of sand. Each cylinder has a radius of 4 inche
ryzh [129]
Part A.
We are given the total volume of the amount of sand she will want to fill
we are also given the shape and dimensions of the cylinders
Total volume of the sand = 1,000
Cylinder= radius 4 in, and height 8 in
the volume of a cylinder is V=πr^2h
We will solve for the volume of the cylinders
V=πr^2hV=π(4)^2*(10)
V = π (16) * (10)
V = π 160
The volume of the cylinders she wants to fill is 502.65 in^3
How many cylinders will she need
Well,
1000/502.65 <span>≈ 1.98
She will need two cylinder cans to fill with the 1,000 in^3 of sand

Part B.
To see if this is true, we find the half of the original cylinder's radius and height then solve for the volume and compare
</span>V=πr^2h
<span>The height and radius of the original cylinders were 4 r and 8h
we will find half of that which will be : 2 r and 4 h
Now solve for the volume </span>V=πr^2h
V=π(2)^2* (4)
V=π (4)*(4)
V = π 16
V ≈<span> 50.26  inches ^3
The volume of the original cylinders was </span>502.65 in^3 and the volume of the new cylinders is 50.26 in^3...  Clearly the volume of the new cylinders is NOT half of the original. Sally is not correct!
<span>
Hope this helps :)

</span>
7 0
3 years ago
A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n
ki77a [65]

Answer:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0
3 years ago
Solve. Please show your work
Sphinxa [80]

Answer:

128

Step-by-step explanation:

8^2√2^2

64√2^2              rewrite √2^2 as 2

64*2

=128

5 0
3 years ago
What is the length of the diagonal from vertex J to vertex L in the quadrilateral below?
kiruha [24]

Answer:

https://www.beatstars.com/yvngstar

Step-by-step explanation: buy 3 beats on their will get you unlimited answers for any grade and any subject for free. :) you welcome

8 0
3 years ago
Read 2 more answers
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