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Xelga [282]
2 years ago
6

The amount of snowfall in January was 2 and 3/5

Mathematics
1 answer:
dolphi86 [110]2 years ago
7 0

2 3/5 - 1 1/3 = 2 6/15 - 1 5/15 = 1 1/5

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I need help with 1 and 3 please
schepotkina [342]
For #1
city A's mean would be 10.5, then you would divide it by the number of numbers there is which is 5,So 10.5/5 is 2.1

city B's mean would be 11.6  then you would divide it by the number of numbers there is which is 5, So 11.6/5 is 2.32.

thats all I have don't know how to do #3 sorry 
4 0
3 years ago
Which shows the prime factorization of 80? Check all that apply. 2 × 4 × 10 2 × 2 × 2 × 2 × 5 24 × 5 2 × 5 × 8
TEA [102]

Answer:

The Prime Factorization of 80 is,  2 × 4 × 10, 2 × 2 × 2 × 2 × 5  and  2 × 4 × 10

Step-by-step explanation: They are correct, because they all equal 80. 2 × 4 × 10=80 and  2 × 4 × 10=80, and 2 × 2 × 2 × 2 × 5=80.

24 × 5=120, Therefore it's the only incorrect question.

4 0
3 years ago
Read 2 more answers
If line b is perpendicular to line a, and line c is
Nikolay [14]

Answer:

y=x-2.5

Step-by-step explanation:

If it is perpendicular to a, just like b, it has the same slope, but, it has a y-intercept of 2.5, unlike b, which has a y-intercept of 1

8 0
3 years ago
use the number and decimal to write a number in which the digit 2 is one tenth the value of the digit 2 in 8.524
artcher [175]
I think it is tens or sum look up fractions place value and u will probable  get it

6 0
3 years ago
What is the product in simplest form? State any restrictions on the variable. Please show your work.
mote1985 [20]
You have the following expressions given in the problem above:

 (y^2/y-3)(y^2-y-6/y^2+y)
 
 By applying the exponents properties, you can simplify it, as it shown below:

 (y^2/y-3)(y^2-y-6/y^2+y)
 (y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
 (y^4-y^3-6y^2)/(y^3-2y2-3y)

 Then, you have:
 y^2(y^2-y-6)/y(y^2-2y-3)
 (y^2-y-6)/(y^2-2y-3)

 The answer is: (y^2-y-6)/(y^2-2y-3)

 


 
5 0
3 years ago
Read 2 more answers
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