Answer:
The answer should be D. 120 degrees
Pop ok you see so the answer here would be frantically elastic
Answer:
![=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B8a%2B6%7D%7B%5Cleft%28a-3%5Cright%29%5Cleft%28a%2B3%5Cright%29%7D)
the third option is your answer
Step-by-step explanation:
![\frac{5}{a-3}+\frac{3}{a+3}\\\mathrm{Least\:Common\:Multiplier\:of\:}a-3,\:a+3:\quad \left(a-3\right)\left(a+3\right)\\\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}\\=\frac{5\left(a+3\right)}{\left(a-3\right)\left(a+3\right)}+\frac{3\left(a-3\right)}{\left(a+3\right)\left(a-3\right)}\\\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{5\left(a+3\right)+3\left(a-3\right)}{\left(a-3\right)\left(a+3\right)}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7Ba-3%7D%2B%5Cfrac%7B3%7D%7Ba%2B3%7D%5C%5C%5Cmathrm%7BLeast%5C%3ACommon%5C%3AMultiplier%5C%3Aof%5C%3A%7Da-3%2C%5C%3Aa%2B3%3A%5Cquad%20%5Cleft%28a-3%5Cright%29%5Cleft%28a%2B3%5Cright%29%5C%5C%5Cmathrm%7BAdjust%5C%3AFractions%5C%3Abased%5C%3Aon%5C%3Athe%5C%3ALCM%7D%5C%5C%3D%5Cfrac%7B5%5Cleft%28a%2B3%5Cright%29%7D%7B%5Cleft%28a-3%5Cright%29%5Cleft%28a%2B3%5Cright%29%7D%2B%5Cfrac%7B3%5Cleft%28a-3%5Cright%29%7D%7B%5Cleft%28a%2B3%5Cright%29%5Cleft%28a-3%5Cright%29%7D%5C%5C%5Cmathrm%7BSince%5C%3Athe%5C%3Adenominators%5C%3Aare%5C%3Aequal%2C%5C%3Acombine%5C%3Athe%5C%3Afractions%7D%3A%5Cquad%20%5Cfrac%7Ba%7D%7Bc%7D%5Cpm%20%5Cfrac%7Bb%7D%7Bc%7D%3D%5Cfrac%7Ba%5Cpm%20%5C%3Ab%7D%7Bc%7D%5C%5C%3D%5Cfrac%7B5%5Cleft%28a%2B3%5Cright%29%2B3%5Cleft%28a-3%5Cright%29%7D%7B%5Cleft%28a-3%5Cright%29%5Cleft%28a%2B3%5Cright%29%7D)
![\mathrm{Expand}\:5\left(a+3\right)+3\left(a-3\right):\quad 8a+6\\=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}](https://tex.z-dn.net/?f=%5Cmathrm%7BExpand%7D%5C%3A5%5Cleft%28a%2B3%5Cright%29%2B3%5Cleft%28a-3%5Cright%29%3A%5Cquad%208a%2B6%5C%5C%3D%5Cfrac%7B8a%2B6%7D%7B%5Cleft%28a-3%5Cright%29%5Cleft%28a%2B3%5Cright%29%7D)
Answer:
A
Step-by-step explanation:
read the question properly
check the picture below.
so the playground is really just 3 rectangles and one triangle, now the triangle has a base of 8 and a height of 6. We can simply get the area of each figure, sum them up and that's the area of the playground.
![\bf \stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(8)(6)}~~+~~\stackrel{\textit{rectangle}}{(8\cdot 8)}~~+~~\stackrel{\textit{rectangle}}{(6\cdot 6)}~~+~~\stackrel{\textit{rectangle}}{(9\cdot 4)} \\\\\\ 24+64+36+36\implies 160](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20triangle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%288%29%286%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Brectangle%7D%7D%7B%288%5Ccdot%208%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Brectangle%7D%7D%7B%286%5Ccdot%206%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Brectangle%7D%7D%7B%289%5Ccdot%204%29%7D%0A%5C%5C%5C%5C%5C%5C%0A24%2B64%2B36%2B36%5Cimplies%20160%20)