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Wewaii [24]
3 years ago
8

Consider the line y = 3/8x + 3

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

Perpendicular line y = (- 8/3)x - 76/3.

Parallel line y = (3/8)x - 1

Step-by-step explanation:

y = 3/8

x + 3

1) Perpendicular line has negative reciprocal slope.

m = - 8/3

y = (- 8/3)x + b

Point (-8, - 4)

- 4 = (- 8/3)*(-8) + b

-4 - 64/3 = b

b = - 76/3

y = (- 8/3)x - 76/3

2) Parallel line has the same slope.

m = 3/8

y = (3/8)x + b

Point (-8, -4)

- 4 = (3/8)*(- 8) + b

- 4 + 3 = b

b = - 1

y = (3/8)x - 1

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Help me plz i have been trying to figure it out forever
OleMash [197]

Answer:

y=3x-4

Step-by-step explanation:

The slope of the line is 3/1, 3 being the rise and 1 being the run. That's how you know that 3 is always going to be multiplied by x.

The -4 part is found by seeing where the line intersects with the y axis. Since the line crosses the y axis at -4, the equation will include -4.

6 0
3 years ago
Read 2 more answers
tom and lisa each had a birthday party at hurricane harbor last weekend . the cost of admission was $137.50 for 13 children and
gregori [183]

Answer:

Per child admission costs $8.5

Per Adult admission costs $13.5

Step-by-step explanation:

Let x be the amount of admission per child and y be the amount of admission per adult

For Tom's party:

13x+2y=137.50      (Equation 1)

For Lisa's Party:

9x+2y=105.50       (Equation 2)

Using Elimination Method:

Add Equation 1 & 2

13x+2y=137.50

9x+2y=105.50  

-    -   = -         (Change of Signs)

---------------------------------

4x+0y=34.00      

x=34/4

x=8.5

Putting the value of x in Equation 2

13(8.5)+2y=137.50

110.5+2y=137.50

2y=137.50-110.50

2y=27

y=27/2

y=13.5

4 0
3 years ago
X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!
7 0
3 years ago
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xenn [34]

Answer:

{-3, 2}U{2, 5}

Step-by-step explanation:

For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.

Therefore, the first set of negative values is (-3, 2).

Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).

The negative values are {-3, 2}U{2, 5}.

6 0
4 years ago
How’s ur day?is it great
Archy [21]
It’s great how’s your day
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