Question

Roxy is multiplying 1/8 by 4/3 . Use the drop-down menu to complete the statement.

Answer 1

Answer:

The product of $\frac{1}{8} \times \frac{4}{3}$ is greater than $\frac{1}{8}$.

Step-by-step explanation:

Given Roxy is multiplying numbers $\frac{1}{8}$  by  $\frac{4}{3}$

$\Rightarrow \frac{1}{8} \times \frac{4}{3}=\frac{1}{6}$

we have to find out which fraction is greater $\frac{1}{6}$  or  $\frac{1}{8}$

Comparing the two fractions,

Step 1) Find the least common denominator or LCM of the two denominators:  

LCM of 6 and 8 is 24

Step 2) For the 1st fraction, since 6 × 4 = 24,

$\frac{1}{6}=\frac{1 \times 4}{6 \times 4}=\frac{4}{24}$

Step 3)  for the 2nd fraction, since 8 × 3 = 24,

$\frac{1}{8}=\frac{1 \times 3}{8 \times 3}=\frac{3}{24}$

Step 4) Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction.

Thus, $\frac{4}{24}>\frac{3}{24}$

$\Rightarrow \frac{1}{6}>\frac{1}{8}$

Thus, the product of $\frac{1}{8} \times \frac{4}{3}>\frac{1}{8}$.

Answer 2

Answer:

The product 1/8 times 4/3 is greater than 1/8.

Step-by-step explanation:

We need to check whether the product of 1/8 and 4/3 is greater than or less than 1/8.

First find the product of 1/8 and 4/3.

$Product=\frac{1}{8}\times \frac{4}{3}$

$Product=\frac{1\times 4}{8\times 3}$

$Product=\frac{4}{24}$

$Product=\frac{1}{6}$

We have to check 1/6 is more than or less that 1/8.

Make denominator common we get

$\frac{1}{6}=\frac{1\times 8}{6\times 8}=\frac{8}{48}$

$\frac{1}{8}=\frac{1\times 6}{8\times 6}=\frac{6}{48}$

So, we conclude that

$\frac{1}{6}>\frac{1}{8}$

It means

$\frac{1}{8}\times \frac{4}{3}>\frac{1}{8}$

Therefore, the product 1/8 times 4/3 is greater than 1/8.