Answer: d=sqrt(41) =6.4031
Step-by-step explanation:
We know that the distance between the two points (x 1 ,y 1 ) and (x 2 ,y 2
) is
d= sqrt((x2-x1)^2 +(y2-y1)^2 )
as given
x1=2 ,x2=6 ,y1=3 ,y2=8
d=sqrt((6-2)^2+(8-3)^2 )
d= sqrt((4)^2+(5)^2
d=sqrt(16+25)
d=sqrt(41) =6.4031
Answer:
Step-by-step explanation:
We can solve this in either of two approaches: Mathematically or Graphically.
<u>Mathematically</u>
y=-(3/4)(x-4)^2+12 where y is the height of the ball, and x is the time, in seconds.
We want to know how many seconds for the height to be 0, so y=0.
0 = -(3/4)(x-4)^2+12
-12 = -(3/4)(x-4)^2
12*(4/3) = (x-4)^2
16 = (x-4)^2
x = 8 and 0 (the initial point).]
It will reach the ground in 8 seconds
<u>Graphically</u>
Plot the function and find the time, x, when the graph passes through the x axis (after t = 0). Attached.
Well 3x(pumpkin) + 1x ( beans ) =4x so 4x=76
divide 76 by four to get x=19
so 19 cans of beans
Answer:
ty but i dont see anything have a blessed day too
Step-by-step explanation:
Answer:
114 Feet^2
Step-by-step explanation:
Volume is length*width*height
So we can cut our shape into 2 rectanges.
The bottom one will have the dimensions of 6*1*3 which is 18 feet
And the top one will have the dimensions of 8*4*3 which is 96 feet
Add them up, 96+18=114 feet