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3 years ago

i have a test tomorrow about writing ratios in different ways i'm not sure how to tho. How do u do that????????!!!!HELP!!!!!

2 answers:

7 0

One way to write a ratio, is as a fraction. For example, you have 6/8, right, so now you basically rewrite that, but instead of the (/) sign, you put the (:) sign, which we normally use for writing ratios. That's the most common way of writing ratios, but also, you can do this;
*you have the same fraction, 6/8, but you basically say it in words. (six to eight) that's exactly how you would say it in words. Remember, your first number thats given is the number you ALWAYS write, or say first

Sphinxa [80]3 years ago

5 0

There are 3 different ways to write a ratio this first is a fraction, 5/8. You could also write it using the word "to", 5 to 8. Finally you could write it using a colon, 5:8. Hope this clears things up for you!

You might be interested in

Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant

alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z) is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0

2 years ago

Which of the following does not dissolve in water

xeze [42]

Answer:

mud

Step-by-step explanation:

4 0

2 years ago

The equation h(t)= -16t^2+864t models the path of a rocket shot into the air. After how many seconds does the rocket hit the gro

Vika [28.1K]

Answer:

t = 54 seconds

Step-by-step explanation:

The equation that models the path of a rocket into the air is given by :

$h(t)= -16t^2+864t$

It is required to find the time after which the rocket will hit the ground. When it hits the ground, the height of the rocket will becomes zero. It means,

h(t) = 0

i.e.

$-16t^2+864t=0\\\\16t(-t+54)=0\\\\16t=0, -t+54=0\\\\t=0\ and\ t=54\ s$

It means after 54 seconds, the rocket will hit the ground.

8 0

3 years ago

Find the sum of the arithmetic sequence. 5,7,9,11,...,23

eduard

Answer:

140

Step-by-step explanation:

The arithmetic series is 5, 7, 9, 11, ........., 23.

First u have to determine the no. of terms that can be done by using

Tₙ = [a + (n - 1)d]

Tₙ-------nth term

a---------first term

n---------no.of terms in the series

d---------common difference

here a = 5,d = 2.

let it contain n terms Tₙ= [a + (n-1)d]

Substitute Tₙ, a, and d in the equation

23 = 5 + (n - 1)2

Subtract 5 from each side.

18 = (n-1)2

Divide each side by 2

(n - 1) = 9

Add 1 to each side

n = 9 + 1 = 10

The sum of the arithmetic sequence formula: Sₙ= (n/2)[2a+(n-1)d]

Substitute Sₙ, a, n and d in the equation

Sₙ= (10/2)[2(5) + (10-1)2]

Sₙ= (5)[10 + (9)2]

Sₙ= 5[10 + 18]

Sₙ= 5[28] = 140

Therefore the sum of the arithmetic sequence is 140.

6 0

2 years ago

the population of a country double every 10 years from 1950 to 1980.what was the percentage increase in population during this t

fredd [130]

700% increase.

Step-by-step explanation:

The duration was 3 decades, or 30 years. The population starts at 100%, then doubles to 200% (decade 1), then 400% (decade 2), then 800% (decade 3).

800% - 100% = 700%

3 0

3 years ago