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3 years ago

What is the area of the figure? Enter your answer in the box. _in²

Mathematics

2 answers:

just olya [345]3 years ago

8 0

Area of triangle (1/2bh)
1/2(4)*6
2*6=12
Area of square (bh)
10*10=100
100+12=112
Area of the figure : 112in^2

mamaluj [8]3 years ago

7 0

$\frac{1}{2} \times 6 \times 4 + 10 \times 10$
= 112 (sorry if there's any mistake)

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A hot air balloon holds 3,249 cubic meters of helium. The density of helium is 0.1785 kilograms per cubic meter. How many kilogr

professor190 [17]

We find the answer by using the density formula: d =m/v
We know the density: 0.1785
We know the volume: 3,249
We DO NOT know the mass, so that is what we're trying to finding
0.1785 = m/3,249
Solve:
3,249 * 0.1785 = m/3,249 * 3,249
579.9465 which can be rounded to 579.9
The answer is D.

5 0

3 years ago

Read 2 more answers

posledela

Answer:

6(x-8)=5-2x

Step-by-step explanation:

let the number be x

so we have six times the difference between a number and 8

that is 6(x-8).

is equal to 5 less than twice the number ..we have

=5-2x.

therefore, our answer becomes:

6(x-8)=5-2x

5 0

3 years ago

NEED HELP ASAP Given G (-6,5) and H (2, -7), what is the length of GH

lesya692 [45]

$\bold{\huge{\green{\underline{ Solution }}}}$

$\bold{\underline{ Given}}$

We have given that the coordinates of the end point G and H are ( -6,5) and ( 2, -7 )

$\bold{\underline{To \: Find :- }}$

We have to find the length of GH

$\bold{\underline{Let's \: Begin :- }}$

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

According to the distance formula, we get :- 

$\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

Here, x1 = -6 , x2 = 2 and y1 = 5 , y2 = -7

Subsitute the required values in the above formula 

$\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}$

$\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}$

$\sf{Distance\:GH=√(-8)^2+(12)^2}$

$\sf{ Distance \:GH =√64 + 144 }$

$\sf{ Distance \:GH =√ 208}$

$\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}$

$\sf{ Distance \:GH = 4√13}$

$\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}$

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2 years ago

May someone please help?

Ronch [10]

(-7,3) here is the answer, easy one

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3 years ago

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Eric made a scale drawing of the auditorium. The stage, which 15 35 feet wide in real life,

Molodets [167]

Based on the given conditions, formulate: 5/35
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2 years ago