What is the solution of the system? Use the elimination method. 2x+y=206x−5y=12 . Enter your answer in the boxes.
2 answers:
2x+y=206x-5y=12
y+204x-5y=12
6y=204x=12
5y=208x=12
you basically put the 2x with 206x. add the 5y to the leftover y in the beginning of equation.
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Answer:
0 = (3-2x) x (x x 2 -5)
(3-2x) x ( x x 2 - 5) = 0
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Step-by-step explanation:
hoped I helped:)