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Feliz [49]
3 years ago
6

What is an equation of the line that is parallel to y= -4x-5 and passes through the point (-2,6)?

Mathematics
2 answers:
lianna [129]3 years ago
6 0

Answer:

y = -4x - 2

Step-by-step explanation:

hjlf3 years ago
4 0

Answer:

y = -4x - 2

Step-by-step explanation:

This line y= -4x-5  has slope = -4

Parallel line, slope is the same so slope of the new line is also = -4

Passes through the point (-2,6), equation:

y - 6 = -4(x + 2)

y - 6 = -4x - 8

y = -4x - 2

Answer:

y = -4x - 2

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The chemical element einsteinium-
AURORKA [14]

Answer:

Every week, the mass of the sample is multiplied by a factor of 0.81

Step-by-step explanation:

Let's rewrite the base and find the expression whose exponent is just ttt.

(0.97)7t+5=(0.97)7t⋅(0.97)5=(0.977)t⋅(0.97)5

Therefore, we can rewrite the modeling function as follows.

M(t)=(0.97)5⋅(0.977)t

According to this model, the mass of the sample is multiplied by 0.977 every week. Rounding this to two decimal places, we get 0.977≈0.81.

7 0
3 years ago
What is the substitution for 3x+4y^2 if x= -2 and y=3?
solniwko [45]

Answer:

<h2>30</h2>

Step-by-step explanation:

3x+4y^2\\\\\text{Substitute the value of x = -2 and y = 3 to the expression:}\\\\3(-2)+4(3^2)\qquad\text{use PEMDAS}\\\\=-6+4(9)=-6+36=30

5 0
3 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
PLEASE HELP ME QUICKKK, FIRST CORRECT PERSON GETS BRAINLIEST​
german

Answer:

The answer is Tennesse

Step-by-step explanation:

because it raises the prices by $45.50

8 0
2 years ago
What set of reflections would carry rectangle ABCD onto itself?
Furkat [3]
Answer: option <span>D) y=x, x-axis, y=x, y-axis</span>.

I first thought it was the option C) and I tried with it but it was wrong. This is how I dit it.

Option C step by step:

<span>1) Reflection over the x - axis => point with coordinates (a,b) is transformed into point with coordinates (a, -b)

2) Reflection over the line y = x  => point with coordinates (a, -b) is transformed into point with coordinates (-b,a)

3) New feflection over the x - axis => (-b,a) transforms into (-b, -a)

4) New reflection over the line y = x => (-b,-a) transforms into (-a,-b)

Which shows it is not the option C).

Then I probed with option D. Step by step:

1) Reflection over the line y = x => (a,b) → (b,a)

2) Reflection over the x-axis => (b,a) → (b,-a)

3) Reflection over the line y = x => (b,-a) → (-a,b)

4) Reflection over the y-axis => (-a,b) → (a,b).

So, this set of reflections, given by the option D) transforms any point into itself, which proofs that the option D) is the right answer.
</span>
7 0
3 years ago
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