Write the equation of the line in point-slope form.<br><br> (-3,2) and (-1,-2)

Thomas reads 2/9 of a book on Monday and 1/6 of it on Tuesday. He reads twice as many pages on Wednesday as on Tuesday. What fra

dezoksy [38]

1/18 is left. Thomas has 1/18 left of his book. How? What denominator can 9&6 relate to? 54? Sure, but it could be lower. How about 18? Ok. We have 18 because 9x2 and 6x3 both equal 18... 2/9 becomes 4/18 because 18 divided by 9 is 2. You multiply 2 with the two from 2/9. 1/6 becomes 3/18 because 18 divided by 6 is 3. You then multiply 3 with the one from 1/6. Put it together and TA-DA... Your answer is 1/18

8 0

3 years ago

3x + 7y = 21 –3x – 7y = 42<br> Solve the system of equations?

likoan [24]

9514 1404 393

Answer:

no solution

Step-by-step explanation:

The equations describe parallel lines. There are no values of x and y that will satisfy both equations.

In standard form, the two equations are ...

3x +7y = 21

3x +7y = -42 . . . . . with positive leading coefficient

If (x, y) values satisfy the first equation, they cannot satisfy the second equation, and vice versa.

8 0

3 years ago

A coin is tossed 5 times. Find the probability that all are heads. Find the probability that at most 2 are heads.

fenix001 [56]

Answer:

1/32

15/32

Step-by-step explanation:

For a fair sided coin,

Probability of heads, P(H) = 1/2

Probability of tails P(T) = 1/2

For a coin tossed 5 times,

P( All heads)

= P(HHHHH),

= P (H) x P(H) x P(H) x P(H) x P(H)

= (1/2) x (1/2) x (1/2) x (1/2) x (1/2)

= 1/32 (Ans)

For part B, it is easier to just list the possible outcomes for

"at most 2 heads" aka "could be 1 head" or "could be 2 heads"

"One Head" Outcomes:

P(HTTTT), P(THTTT) P(TTHTT), P(TTTHT), P(TTTTH)

"2 Heads" Outcomes:

P(HHTTT), P(HTHTT), P(HTTHT), P(HTTTH), P(THHTT), P(THTHT), P(THTTH), P(TTHHT), P(TTHTH), P(TTTHH)

If we count all the possible outcomes, we get 15 possible outcomes representing "at most 2 heads)

we know that each outcome has a probability of 1/32

hence 15 outcomes for "at most 2 heads" have a probability of

(1/32) x 15 = 15/32

8 0

3 years ago

Read 2 more answers

3. Are these ratios equivalent? 35:28 and 10:8 *

attashe74 [19]

Reduce each ratio to its minimum expression to find if they are equal.

35:28

$\begin{gathered} \frac{35}{28}=\frac{7\cdot5}{7\cdot4} \\ =\frac{5}{4} \end{gathered}$

10:8

$\begin{gathered} \frac{10}{8}=\frac{2\cdot5}{2\cdot4} \\ =\frac{5}{4} \end{gathered}$

Since both ratios reduce to 5:4, they are equivalent.

Another way to check a:b is equivalent to c:d, is that a*d = b*c

In this case, this will be true if 35 times 8 is equal to 10 times 28:

$\begin{gathered} 35\cdot8=280 \\ 10\cdot28=280 \end{gathered}$

Since both products are equal, then the ratios are equivalent.

4 0

1 year ago

The number of orders received daily by an online vendor of used CDs is normally distributed with mean 270 and standard deviation

frez [133]

Answer:

Step-by-step explanation:

Given that the number of orders received daily by an online vendor of used CDs (say X) is normally distributed with mean 270 and standard deviation 16.

X is N(270, 16)

To find percentage of days will the company have to hire extra help or pay overtime, we can find probability using std normal table

X>302 means

$Z>\frac{302-270}{16} =2$

P(Z>2) = 0.25

Thus 25% of days will the company have to hire extra help or pay overtime

4 0

3 years ago

Write the equation of the line in point-slope form. (-3,2) and (-1,-2)