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3 years ago

Write the equation of the line in point-slope form. (-3,2) and (-1,-2)

Mathematics

1 answer:

tester [92]3 years ago

4 0

Answer:

y=-2x-4

Step-by-step explanation:

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3 years ago

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The graph has lines that are what

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Write an equation of the line whose slope and y-intercept are respectively:

bezimeni [28]

2 and 7 because it will stay constant

5 0

3 years ago

Find the average value fave of the function f on the given interval. f() = 5 sec2(/6), 0, 3 2

Inessa05 [86]

Answer:

$f_{ave}$ = ${\frac{10 }{3\pi }$

Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3 $\pi$ /2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

$f_{ave}$ = $\frac{1}{b - a}\int\limits^b_a {f(x)} \, dx$

Now,

Here a = 0, b = $\frac{3\pi }{2}$ , f(x) = $5sec^{2}(\frac{x}{6} )$

Now,

$f_{ave}$ = $\frac{1}{\frac{3\pi }{2} - 0}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx$

= ${\frac{2 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx$

= ${\frac{10 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {sec^2 ({\frac{x}{6} }) } \, dx$

= ${\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ]$

= ${\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ]$

= ${\frac{10 }{3\pi }}[ {1 - 0 } ]$

= ${\frac{10 }{3\pi }$

⇒ $f_{ave}$ = ${\frac{10 }{3\pi }$

3 0

3 years ago

Could someone just explain how to solve this for the two sides? We learned 30 60 90 triangles not 29 61 90 triangles

natta225 [31]

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

Side a is adjacent to the 29° angle, and 14 is opposite of the 29° angle. So use tangent:

tan 29° = 14 / a

a = 14 / tan 29°

a ≈ 25.3

Side c is the hypotenuse, and 14 is opposite of the 29° angle. So use sine:

sin 29° = 14 / c

c = 14 / sin 29°

c ≈ 28.9

5 0

4 years ago