


with that template in mind, let's see

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
Answer:
4.5 hours
Step-by-step explanation:
8:2h = 18:x
8x = 18×2h
x = 36h/8
x = 4.5
hope this helps :)
Answer:
d = 12.21
Step-by-step explanation:
1) Subtract 4 from both sides.
d = 16.21 - 4
2) Simplify 16.21 - 4 to 12.21.
d = 12.21
Check the answer!
⇒ d + 4 = 16.21
1. Let d = 12.21.
⇒ 12.21 + 4 = 16.21
2. Simplify 12.21 + 4 to 16.21
16.21 = 16.21
Done!
Thanks,
Eddie
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
Answer:
they are perpendicular
Step-by-step explanation :
<u>If you graph both equations you will see that they Intersect with each other.</u><u>
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