F(x,n,p)=C(n,x)p^x*(1-p)^(n-x)
n=9, p=0.8 =>
f(x,9,0.8)=C(9,x)0.8^x*(0.2)^(9-x)
The function f(x,9,0.8) is then calculated using the above formula
x f(x)
0 0.0000001 0.0000182 0.0002953 0.0027534 0.0165155 0.0660606 0.1761617 0.3019908 0.3019909 0.134218
Check Sum f(x), [x=0,9] = 1.0 ok
Answer:
433
Step-by-step explanation:
When there are 2 neatives together like that it changes to a positive. So it woud be 329+104=433
The given equation is:
ax2 + bx + c = 0
We have the resolvent is:
x = (- b +/- root (b2 - 4ac)) / (2a)
The discriminant is:
b2 - 4ac = 0
The solution will be:
x = (- b) / (2a)
Thus, the equation has a real solution.
Answer:
option B
