All categories

2 years ago

Plz help will choose brainliest!

Mathematics

1 answer:

Allisa [31]2 years ago

3 0

Answer:

D, E, F

Step-by-step explanation:

The first step I would do is distribute the original equation. After distributing, the equation is now 8x² + 16xy. The first answer I see that matches this is D.

Then, after already eliminating A, B, and C, I look at E. I distribute the x and find out it is also equal to 8x² + 16xy.

Then, I look at F. After distributing again, it is also equal to 8x² + 16xy.

You might be interested in

The County Fair has to 2 ticket options.Option 1 has an entry fee of $5 and charges $0.65 per ride per ride. Option 2 has an ent

Ugo [173]

For 25 tickets total cost of option one and option two to be the same.

Step-by-step explanation:

Let us assume the total number of rides = m

for which BOTH options cost same.

Case: 1

The cost of entry fee = $5

The cost per ride = $0.65

So, the cost of m rides = m x ( Cost of 1 ride )

= m x ($0.65 ) = 0.65 m

Cost of purchasing m tickets in first ride = Entry Fee + Per ticket cost

= 5 +0.65 m ..... (1)

Case: 2

The cost of entry fee = $10

The cost per ride = $0.45

So, the cost of m rides = m x ( Cost of 1 ride )

= m x ($0.45 ) = 0.45 m

Cost of purchasing m tickets in second ride = Entry Fee + Per ticket cost

= 10 +0.45 m ..... (2)

Now, equating (1) and (2), we get:

5 +0.65 m = 10 +0.45 m

or, 0.20 m = 5

or, m = 5/0.20 = 25

or, m = 25

Hence, for 25 tickets total cost of option one and option two to be the same.

5 0

2 years ago

Please help me with this math problem :)

telo118 [61]

The correct answer is C. hope this helps

4 0

2 years ago

Which set or sets does the number 15 belong to

8_murik_8 [283]

Rational,whole,integer,real

4 0

2 years ago

Read 2 more answers

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

2 years ago

Heidi solved the equation 3(x + 4) + 2 = 2 + 5(x – 4). Her steps are below: 3x + 12 + 2 = 2 + 5x – 20 3x + 14 = 5x – 18 14 = 2x

lyudmila [28]

Answer:

See explanation

Step-by-step explanation:

3(x + 4) + 2 = 2 + 5(x – 4)

Step 1: distributive property

3(x + 4) + 2 = 2 + 5(x – 4)

3x + 12 + 2 = 2 + 5x - 20

Step 2: collect like terms

3x + 12 + 2 = 2 + 5x - 20

3x + 14 = 5x - 18

Step 3: Addition property of equality

3x + 14 = 5x - 18

3x + 14 + 18 = 5x - 18 + 18

3x + 32 = 5x

Step 4: subtraction property of equality

3x + 32 - 3x = 5x - 3x

32 = 2x

Step 5: division property of equality

32 = 2x

32/2 = 2x/2

16 = x

x = 16

6 0

1 year ago