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3 years ago

She rides for 17.6 kilometers at a speed of 11 kilometers per hour. For how many hours does she ride?

Mathematics

2 answers:

inn [45]3 years ago

8 0

Speed = Distance/Time

Time = Distance/Speed

Time = 17.6/11

= 1.6 hrs

Salsk061 [2.6K]3 years ago

5 0

Let us assume Latoya is driving the car.

Answer:

1.6 hrs took by latoya to cover the distance.

Step-by-step explanation:

We have been given that latoya is riding his bicycle. He rides at a speed of 11 kilometers per hour for 17.6

Let's write the data in simplest form.

Total distance covered by dale = 17.6 km

Speed of bicycle = 11 km/hr

We have to find the time taken by latoya to cover the distance.

Here, Time is given by distance / Speed.

Time = Distance/Speed

Time = 17.6/ 11

Time = 1.6 hr

Therefore, 1.6 hrs took by latoya to cover the distance.

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Answer:

1) x=10

2) x=6

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Step-by-step explanation:

1) 15x-17+4x+7=180

19x-10=180

19x=190

x=10

2) 13x+5=16x-13

5+13=16x-13x

18=3x

x=6

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3 years ago

Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.

dalvyx [7]

Answer:

The measure of the side $QR$ is 8.8.

Step-by-step explanation:

Since $LMNO \sim PQRS$ , then $SP \propto OL$ , $RS \propto ON$ , $RQ \propto MN$ and $QP \propto LM$ . From figure we have the following relationship:

$k = \frac{OL}{SP} = \frac{ON}{RS} = \frac{MN}{QR} = \frac{ML}{QP}$ (1)

Where $k$ is the proportionality ratio.

If we know that $SP = 13, OL = 55, MN = 37$ , then the measure of side $QR$ is:

$k = \frac{OL}{SP}$ (1b)

$k = \frac{55}{13}$

$k = \frac{MN}{QR}$

$QR = \frac{MN}{k}$ (1c)

$QR = \frac{37}{\frac{55}{13} }$

$QR = 8.745$

The measure of the side $QR$ is 8.8.

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3 years ago

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Fantom [35]

We are given y = kxz
We also know 32 = k×6×8, so k = 32/48 = 2/3.
We are then asked to solve:

$y = \frac{2}{3} \times 5 \times 12 = 40$

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