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3 years ago

Which angle is vertical <EFA

Mathematics

1 answer:

zimovet [89]3 years ago

5 0

Angles that are vertical are basically neighbors that are across from each other (numbers across from each other).

Angle <CFD would be vertical to <EFA.

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Double the expression 8x-3.55

kobusy [5.1K]

16x-7.1 is the doubled version of that expression

7 0

3 years ago

Read 2 more answers

Please help. I don’t understand this math problem . I’ll mark you as brainliest if correct

Luba_88 [7]

Answer:

$f(x)=3\log_4{(2-x)}$

Step-by-step explanation:

You know that a log function has a vertical asymptote at x=0 and an x-intercept at (1, 0). It trends upward to the right.

The given graph has a vertical asymptote at x=2, indicating the transformation involves a right-shift of 2 units. It trends upward to the left of the vertical asymptote, suggesting a reflection is involved. At 1 unit left of the vertical asymptote, the graph crosses y=0, so there is no horizontal scaling involved.

At this point, you can write a version of the function f(x) that incorporates the reflection and translation:

f(x) = k·log(-(x -2)) = k·log(2-x)

To find the vertical scale factor k, we make use of the additional point that is given.

f(-2) = 3

k·log(2 -(-2)) = 3 . . . . substitute into our f(x) so far

k = 3/log(4) . . . . . . . . solve for k

Now, the function can be written as ...

$f(x)=\dfrac{3}{\log{4}}\log{(2-x)}=3\dfrac{\log{(2-x)}}{\log{4}}$

Using the "change of base" formula for logarithms we can compact this to ...

$\boxed{f(x)=3\log_4{(2-x)}}$

8 0

3 years ago

Please help meee oh please

irakobra [83]

Collecting the data of this P.G., comes:

The 1st term $a_{1} = 648$ 
The 2nd term $a_{2} = 216$ 

The ratio $r = \frac {a2}{a1} 
$ 
The number of terms n = 8

The 8th term $a_{8} = ?$

The value of ratio, we have:
The ratio $r = \frac {a2}{a1}$
$r = \frac {a2}{a1} = \frac{216}{648} \frac{\div6}{\div6} = \frac{36}{108} \frac{\div6}{\div6} = \frac{6}{18} \frac{\div6}{\div6} \to\:r= \frac{1}{3}$

Applying the general term formula of P.G., comes:
 $a_{n} = a_{1} *r^{n-1}$
$a_{8} = 648 * (\frac{1}{3}) ^{8-1}$
$a_{8} = 648 * (\frac{1}{3}) ^{7}$
$a_{8} = 648 * \frac{1}{3^7}$
$a_{8} = 648 * \frac{1}{2187}$
$a_{8} = \frac{648}{2187}$
Simplify

$a_{8} = \frac{648}{2187} \frac{\div9}{\div9} = \frac{72}{243} \frac{\div9}{\div9} \to\: \boxed{\boxed{a_{8} = \frac{8}{27}}}\end{array}}\qquad\quad\checkmark$

Answer:
$\boxed{\boxed{a_{8} = \frac{8}{27}}}$

6 0

4 years ago

The measure of an angle is three times the measure of its supplementary angle. What is the measure of each angle?

Agata [3.3K]

Answer:

Angle = 135°

Supplement of the Angle = 45°

Step-by-step explanation:

The complement of an angle, say "x", would be 90 minus that angle:

90 - x

The supplement of an angle, say "y", would be 180 minus that angle:

180 - y

Since we have 1 angle, let it be "x", and that angle is 3 TIMES the SUPPLEMENT of that angle, we can write:

x = 3(180 - x)

Now, we solve for the angle x:

$x = 3(180 - x)\\x = 540 - 3x\\x + 3x = 540\\4x = 540\\x = \frac{540}{4}\\x=135$

So, the angle is 135°

The supplement of the angle is 180 - 135 = 45°

4 0

3 years ago

I need help on this problem 6j-3 for j=4

VARVARA [1.3K]

Answer:

Step-by-step explanation:

6j - 3

6(j)-3

if j = 4

then 6(4)-3

parentheses w/out any other symbol is multiplication

so 6 * 4 = 24

24-3

24-3 = 21

5 0

4 years ago