When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
C=14pi cm
A=49pi cm^2
Step-by-step explanation:
1) Circumference of a circle is 2piR and R=7cm
C=2pi(7)
C=14pi cm
2) Area of a circle is piR^2 and R=7cm
A=pi (7)^2
A=49pi cm^2
75.89 + 0.12x = 27.41 + 0.36x
75.89 - 27.41 = 0.24x
48.48 = 0.24x
x = 48.48 / 0.24
x = 202
Each sent 202 text messages
Answer:
3
Step-by-step explanation: