Answer:
10
Step-by-step explanation:
12×5 = 60 in of yarn
60÷6 =10 bracelets
Answer:
c.
Step-by-step explanation:
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
Answer: The answer is (n = 5r + 10).
Step-by-step explanation: Given that in a theatre, there are 15 seats in the first row, 20 seats in the second row, 25 seats in the third row, etc.
We are to write the linear equation that represents the number of seats 'n' in each row 'r'.
Now,
Number of seats in the 1st row = 15 = 5 × 3 = 5 × (1+2),
number of seats in the 2nd row = 20 = 5 × 4 = 5 × (2+2),
number of seats in the 3rd row = 25 = 5 × 5 = 5 × (3+2), etc...
Therefore, number of seats 'n' in the r-th row is given by the following linear equation -
n = 5 × (r+2), i.e., n = 5r + 10.
Thus, the required linear equation is n = 5r + 10.
