Answer: 36
Step-by-step explanation:
Here, the total number of candies in the jars = 250
The fullest jar or left most jar has candies = 72
The right most or least candies containing jar has candies = 13
Thus, the sum of candies of middle 5 jars = 250-(72+13) = 165
The average of the these 5 jar = 165/5 = 33
Thus, the maximum number of candies in the middle jar = 33
⇒ The minimum number of candies in the second jar = 33 + 2 = 35 ( because no jar has equal number of candies and they are put in the decreasing order of candies)
But, the maximum number of candies in the second jar = 72 - 1 = 71
⇒ The difference between the maximum number of candies in second jar = 71 - 35 = 36
3x=x+40
Subtract x from both sides
2x=40
Divide both sides by 2nto get x by itself
x=2
Plug 2 in for x
m∠4 = (3x)
m∠4 = 3(2)
Solve
m∠4 = 6
4/100= 0.04
0.04 x 250 = 10 (This is the interest earned in the year)
250+10 = 260
Take an m out of both variables, m(-2m + 10) = -6
then set each term equal to - 6,
-2m + 10 = 6,
-2m = -4
m = 2 and m = -6