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2 years ago

If f(x) = ||x|| , find f(−14)

Mathematics

2 answers:

tino4ka555 [31]2 years ago

4 0

Answer:

f(-14) = 14

Step-by-step explanation:

Given

f(x) = ||x||

The ||..|| sign represents the double modulus sign or sign of double absolute value.

The absolute value of any number returns the positive value of that number.

To solve this, we first find the inner modulus or absolute value then we find the outer modulus,

If f(x) = ||x||

Then f(x) = |(|x|)| where |x| represents the inner modulus;

To find f(-14).

The inner modulus is |-14|; This returns positive 14

|-14| = 14

Then we solve for the outer modulus (even though it doesn't change anything)

|14| = 14

So, f(-14) = |(|-14|)|

f(-14) = |14|

f(-14) = 14

bogdanovich [222]2 years ago

3 0

Answer:

Step-by-step explanation:

f(-14) = ||-14|| = |14| = 14

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2 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$