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3 years ago

Relationship in the triangle must be true

Mathematics

1 answer:

lilavasa [31]3 years ago

7 0

False that has to be false

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3 years ago

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3 years ago

If p and q vary inversely and pp is 23 when q is 6, determine q when p is equal to 69.

Lina20 [59]

Answer:

Answer is q = 2

Step-by-step explanation:

First make the equation with a constant so p=k/q

then substitute q to 6 and p to 23.

Then you have 23=k/6 and to find k multiply both sides to get k=138

next substitute p as 69=138/q then multiply q on both sides to get 69xq=138 and then divide 69 to 138 go get q which is 2

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1 year ago

Show how 2.03x1.2x0.5 is multiply

Mama L [17]

2.03
×
1.2
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406
+
2030
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6036
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3.0180 either 3.0180 is the anwser or 1.218

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3 years ago

Evalute costheta if sintheta = (sqrt5)/3

torisob [31]

Answer:

$\large\boxed{\cos\theta=\pm\dfrac{2}{3}}$

Step-by-step explanation:

Use $\sin^2x+\cos^2x=1$ .

We have

$\sin\theta=\dfrac{\sqrt5}{3}$

Substitute:

$\left(\dfrac{\sqrt5}{3}\right)^2+\cos^2\theta=1\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(\sqrt5)^2}{3^2}+\cos^2\theta=1\qquad\text{use}\ (\sqrt{a})^2=a\\\\\dfrac{5}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{5}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{9}{9}-\dfrac{5}{9}\\\\\cos^2\theta=\dfrac{4}{9}\to \cos\theta=\pm\sqrt{\dfrac{4}{9}}\\\\\cos\theta=\pm\dfrac{\sqrt4}{\sqrt9}\\\\\cos\theta=\pm\dfrac{2}{3}$

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3 years ago

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