Evalute costheta if sintheta = (sqrt5)/3
2 answers:
Answer: 
Step-by-step explanation:
In this case we know that:

To find the value of
we use the following trigonometric identity

So

Therefore





Answer:

Step-by-step explanation:
Use
.
We have

Substitute:

You might be interested in
Answer:
5/12 first pack
5/10 second pack
Step-by-step explanation:
Now she has 6 watermelons.
Answer:
Domain= x∉Real numbers
Step-by-step explanation:
2 1/2 for $6.25 is the answer
Answer:
16
Step-by-step explanation:
