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4 years ago

____ is an important nutrient for pregnant mothers.

Chemistry

1 answer:

Elanso [62]4 years ago

3 0

Its all of the above.

- I took the test and mine is correct.

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Among the gases listed, which would have the fastest rate of effusion?

Delvig [45]

"CH4" is the one gas among the choices given in the question that would have the fastest rate of effusion. The correct option among all the options that are given in the question is the second option or option "B". I hope that this is the answer that has actually come to your great help.

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3 years ago

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Which state of matter expands when heated and is easy to compress? gas solid liquid

butalik [34]

Answer:

gas

Explanation:

The gas molecules are far apart and as such, when heated they gain more kinetic energy thereby colliding with one another and with the wall of the container thereby exerting pressure and also they can be compressed by reducing the distance between between the molecules.

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3 years ago

How many aluminum atoms are in 2.88 g of aluminum?

alex41 [277]

Answer:

Explanation:

1 Mole of Aluminum with mass 26.98g contains 6.02*10^23 atoms.

In 2.88g of Aluminum, there are 2.88/26.98*6.02*10^23 = 6.426*10^22 atoms.

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3 years ago

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Which best describes nuclear fission?

rewona [7]

Answer:

C. The splitting apart of atomic nuclei

Explanation:

Nuclear fission is the splitting apart of atomic nuclei.

7 0

3 years ago

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

Answer: The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

Explanation:

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

3 years ago