The modified area is (1/48) (2πr(4h+3r))
<u>Step-by-step explanation:</u>
Let the radius be 'r' and height be 'h'.
Area of cylinder= 2π r(h+r)
The radius is shrunk down to quarter of its original radius
r = r/4
The height is reduced to a third of its original height
h = h/3
New Area = 2π(r/4) [(h/3) +(r/4) ]
= (1/4)2πr[(4h+3r) /12]
= (1/48) (2πr(4h+3r))
The answer is x=2
Remember, first add/substract the like terms, in this case 6x-10x to get -4x. Then, add 8x to negative 8x to cancel it out and do the same thing to -4x. Do this with all your terms and you should get 4x=8. Then divide both sides by 4 to get x=2.
Answer:
it's A please mark mine good .............
32% * 25 =
(32*25)/100
800/100=8
8%
