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cricket20 [7]
3 years ago
14

he table gives the probability distribution of the number of books sold in a day at a bookstore. What is the probability of 16 o

r more books being sold on a given day? number of books sold in a day 0-5 6-10 11-15 16-20 21-25 probability 0.110 0.206 0.464 0.201 ? 0.220 0.201 0.464 0.019
Mathematics
1 answer:
Pepsi [2]3 years ago
4 0
16 or more books sold in a day will include two intervals from the given table:

a) 16 - 20 books sold.
Probability = 0.201

b) 21 - 25 books sold.
Probability = ?

Since the table gives the probability distribution, the sum of all the probabilities must be equal to 1. We are given the probabilities of 4 out 5 intervals. So in order to find the probability of the 5th interval (21-25) we can subtract the sum of probabilities of rest of the intervals from 1.
So, P(21 - 25) = 0.019

In order to find the probability of 16 or more books sold we need to sum the probabilities of both these intervals.

So, the probability of 16 or more books being sold on a given day = 0.201 + 0.019 = 0.220
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Use distributive property a(b + c) = ab + ac.

2x(y^2+3)-5(3+y^2)=(2x)(y^2)+(2x)(3)+(-5)(3)+(-5)(y^2)\\\\=2xy^2+6x-15-5y^2

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3 years ago
What is the solution to the following system of equations:<br><br>7x+2y=24<br>8x+2y=30<br>​
GuDViN [60]

Answer:

7x +2y =24 --------- (i)

8x +2y= 30 ---------(ii)

Subtracting eqn. (i) & (ii)

7x +2y =24

8x +2y= 30

- - -

___________

-x = - 6

Putting the value of x in eqn. (i)

7*6 +2y =24

42 +2y =24

2y =-18

y = - 9

Hence, x=6 and y= - 9

Hope it helps!!

3 0
3 years ago
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
BabaBlast [244]

Complete question :

The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.

Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?

Answer:

21 runners

Step-by-step explanation:

Mean, μ = 13 seconds

Standard deviation, σ = 0.3

Lana's race time = 13.2

We find the proportion of runners who had race time above 13.2 ;

Proportion of who had race tune above 13.2

P(x > 13.2)

Obtain the Zscore

Zscore = (x - μ) / σ

Z = (13.2 - 13) / 0.3

Zscore = 0.2 / 0.3 = 0.6667

P(Z > 0.6667) = 0.25239 (Z probability calculator)

This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)

Hence, Number of runners Lana beat = 25% of total runners ;

0.25 * 84 = 21

Hence, Lana beat about 21 runners

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3 years ago
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rusak2 [61]

Answer:

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Step-by-step explanation:

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3 years ago
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galben [10]

Answer: Pretty sure it is 3

Step-by-step explanation:

I think...

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