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mina [271]
3 years ago
14

What is the equation of the line that passes through the point (3,6) and has a slope of 4/3

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

y = 4/3x+2

Step-by-step explanation:

We can use the slope intercept form of the equation

y = mx+b

Where m is the slope and b is the y intercept

y= 4/3 x +b

Substitute the point into the equation

6 = 4/3(3) +b

6 = 4 +b

Subtract 4 from each side

2 = b

y = 4/3x+2

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Refer to the diagram shown.
lions [1.4K]

Answer:

x=5

Step-by-step explanation:

According to SSS, RPS and RPQ should be similar angles. Since the length RP is the same, then RQP and RSP should be similar too. Therefore PRS and PRQ should be similar too. Since QP and RS are the same (7) then QR and PS needs to be same in length too.

2x+3 = 4x-7

10 = 2x

x=5

5 0
3 years ago
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Write 0.735 as a simplified fraction
Arisa [49]

Answer:

73/5

Step-by-step explanation:

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4 years ago
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A company had three divisions with equal number of members. In the beginning of the year the company had a fund of $1200. In add
atroni [7]

Answer:

3 members

Step-by-step explanation:

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3 years ago
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Two numbers have a sum of 761 and a difference of 335.what are the 2 numbers ​
melisa1 [442]

Answer:

548 and 213

Step-by-step explanation:

Use a linear function:

Let x = 1st number

Let y = 2nd number

x+y=761

x-y=335

2x=1096

x=548

plug x into either equation

548+y=761

y=761-548

y=213

548-y=335

-y=-213

y=213

6 0
3 years ago
Lines y and z are parallel.
Mrac [35]

Answer:

28 degrees

Step-by-step explanation:

step 1

Find the measure of angle 1

m\angle 1+65^o=180^o ----> by supplementary angles

m\angle 1=180^o-65^o=115^o

step 2

Find the value of x

(10x+5)^o=m\angle 1 ----> by corresponding angles

substitute

(10x+5)^o=115^o

10x=110\\x=11

step 3

Find the measure of angle 2

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

m\angle 1+m\angle 2+(4x-7)^o=180^o

substitute

115^o+m\angle 2+(4(11)-7)^o=180^o

m\angle 2=180^o-152^o=28^o

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3 years ago
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