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avanturin [10]
3 years ago
15

An electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are l

abeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each. Let A be the event that the first resistor has a resistance greater than 10, let B be the event that the second resistor has a resistance less than 19, and let C be the event that the sum of the resistances is equal to 28. List the sample space for this experiment, and specify the subsets corresponding to the events A, B, and C. Ans:
Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

Step-by-step explanation:

given that an  electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are labeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each

Sample space for selecting one resistor from first box

= {9, 10, 11, 12, 13}

A = {11,12,13} (because >10)

Sample space for selecting one resistor from second  box

={18,19,20,21,22}

B={18}

Sample space for sum would be

{27, 28, 29, 30, 31, 32, 33, 34, 35}

C = {(9,19) , (10,18)}

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Answer:

Step-by-step explanation:

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Read 2 more answers
Charles has a collection of dimes and quarters worth $1.25. He has 8 coins. Write a systems of equations to represent this situa
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Answer:

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

Charles has 5 dimes and 3 quarters

Step-by-step explanation:

* Lets explain how to solve the problem

- Charles has a collection of dimes and quarters worth $1.25

- He has 8 coins

* To solve the problem remember that:

# 1 dim = 10 cents

# 1 quarter = 25 cents

# 1 dollar = 100 cents

- Assume that the number of dimes is d and the number of

 quarter is q

∵ Charles has 8 coins

- The number of dimes and the number of quarters equal the

  number of the coins

∴ d + q = 8 ⇒ (1)

∵ 1 dime = 10 cents

∴ The value of dimes = 10 × d = 10d

∵ 1 quarter = 25 cents

∴ The value of quarters = 25 × q = 25q

∵ The collection worth $1.25

∵ 1 dollar = 100 cents

∴ The collection worth = 1.25 × 100 = 125 cents

∴ 10d + 25q = 125 ⇒ (2)

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

* Lets solve the equations

- Multiply equation (1) by (-10) to eliminate d

∴ -10d + -10q = -80 ⇒ (3)

- Add equations (2) and (3)

∴ 15q = 45

- Divide both sides by 15

∴ q = 3

- Substitute the value of q in equation (1) to find the value of d

∴ d + 3 = 8

- Subtract 3 from both sides

∴ d = 5

∵ d represents the number of dimes and q represents the number

  of quarters

∴ Charles has 5 dimes and 3 quarters

4 0
3 years ago
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