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avanturin [10]
3 years ago
15

An electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are l

abeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each. Let A be the event that the first resistor has a resistance greater than 10, let B be the event that the second resistor has a resistance less than 19, and let C be the event that the sum of the resistances is equal to 28. List the sample space for this experiment, and specify the subsets corresponding to the events A, B, and C. Ans:
Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

Step-by-step explanation:

given that an  electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are labeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each

Sample space for selecting one resistor from first box

= {9, 10, 11, 12, 13}

A = {11,12,13} (because >10)

Sample space for selecting one resistor from second  box

={18,19,20,21,22}

B={18}

Sample space for sum would be

{27, 28, 29, 30, 31, 32, 33, 34, 35}

C = {(9,19) , (10,18)}

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Associations In Data:Question 10
Karo-lina-s [1.5K]

Answer:

\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9

|62-78.9| = 16.9

|63-78.9| = 15.9

|68-78.9| = 10.9

|72-78.9| = 6.9

|79-78.9| = 0.1

|80-78.9| = 1.1

|83-78.9| = 4.1

|93-78.9| = 14.1

|94-78.9| = 15.1

|95-78.9| = 16.1

MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}

And replacing we got:

MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12

And the best anwer is

10.12

Step-by-step explanation:

We have the following data given:

62 63 68 72 79 80 83 93 94 95

And we need to begin finding the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9

Now we can find the mean absolute deviation like this:

|62-78.9| = 16.9

|63-78.9| = 15.9

|68-78.9| = 10.9

|72-78.9| = 6.9

|79-78.9| = 0.1

|80-78.9| = 1.1

|83-78.9| = 4.1

|93-78.9| = 14.1

|94-78.9| = 15.1

|95-78.9| = 16.1

And finally we can find the mean abslute deviation with the following formula:

MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}

And replacing we got:

MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12

And the best anwer is

10.12

8 0
4 years ago
What is 4x+y=6 in slope intercept from.
gtnhenbr [62]
The answer is y=-4x+6
7 0
4 years ago
A penguin can dive 48 meters below the surface of the water to reach a fish. It dives 2% of the total depth every 1 second.
melisa1 [442]
It is 0.96 mps. Did this help
5 0
4 years ago
The sum of two integers is 54 and their difference is 10.
Mama L [17]

Solve for x first

X+y=54

X-y=10


Add


2x=64


Divide

X=64/2


X= 32


So now get one equation and substitute x to solve for y


32+y=54


Y=54-32


Y= 22


So your two numbers is 32 and 22.


To check substitute

32+22=54

32-22=10


They check

7 0
4 years ago
Please help i will give decent points if corrected
madreJ [45]

Answer:

The answer to your question is  

B

Step-by-step explanation:

8 0
3 years ago
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