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Brrunno [24]
3 years ago
9

)) In a right triangle, a and b are the lengths of the legs and c is the length of the

Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

3.008 km or 3.0 km

Step-by-step explanation:

According to the Pythagoras theorem:

{c}^{2}  =  {a}^{2}  +  {b}^{2}  \\  \therefore \:  {a}^{2}  =  {c}^{2}  -  {b}^{2}  \\ \therefore \:  {a}^{2}  =  {(9.3)}^{2}  -  {(8.8)}^{2} \\  \therefore \:  {a}^{2}  =  {(9.3 + 8.8)}{(9.3 - 8.8)} \\ \therefore \:  {a}^{2}  =  18.1 \times 0.5 \\  \therefore \:  {a}^{2}  = 9.05 \\ \therefore \:  {a}  =  \sqrt{9.05}  \\ \therefore \:  {a}  =  3.00832179 \\ \therefore \:  {a}  = 3.0 \: km

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A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500
Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking,\frac{d(w)}{dt} = 3 ft/sec

Rate at which the man is walking,\frac{d(m)}{dt} = 2 ft/sec

Collective rate of both, \frac{d(m+w)}{dt} = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min  = 20 min

Now,

Distance traveled by man and woman are m and w ft respectively.

⇒ m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft

⇒ w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\  ft

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate \frac{dh}{dt} .

Lets calculate h.

Applying Pythagoras formula.

⇒ h^2=(m+w)^2+500^2  

⇒ h=\sqrt{(2400+2700)^2+500^2} = 5124.45

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ h^2=(m+w)^2+500^2

⇒ 2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt}  + \frac{d(500)}{dt}

⇒ \frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}                         ...as \frac{d(500)}{dt}= 0

⇒ Plugging the values.

⇒ \frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}                       ...as \frac{d(m+w)}{dt} = 5 ft/sec

⇒ \frac{d(h)}{dt} =4.9761  ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0
3 years ago
Que es una Progresión Aritméticas
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3 0
2 years ago
What is the result of subtracting a number greater than -3 but less than -2 from a number greater than 1 and less than 6
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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