1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MariettaO [177]
3 years ago
13

What is the result of subtracting a number greater than -3 but less than -2 from a number greater than 1 and less than 6

Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

2/2 - 4 = -3

Step-by-step explanation:

I don't know really but, hopefully this helps. Are there any answer choices?

You might be interested in
The graph of y=f(X) is shown below. Graph y=1/2f(x)
lubasha [3.4K]

Answer:

The grap is a partial line , showing to be negative. The y-int is -3 and the slope is -1/2

Top answer · 0 votes

So then the linear function is y = f(x) = (-1/2)X - 3 y = g(x) = 1/2 * f(x) = (-1/4)x - 3/2 y-intercept is (-1/4)(0) - 3/2 = 0 - 3/2 = -3/2 ... More

3 0
3 years ago
In T-ball, the distance to each successive base is 50 feet. If the distance from home plate to the pitcher’s mound is 38 feet, h
JulijaS [17]

Answer:

<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>

Step-by-step explanation:

The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.

We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

50^{2} =38^{2}+x^{2}\\x^{2}=50^{2}-38^{2}\\x=\sqrt{2500-1444}\\ x=\sqrt{1056}\\ x \approx 32.5 \ ft

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.

Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

50^{2}=32.5^{2}+y^{2}\\y^{2}=50^{2}-32.5^{2}\\y=\sqrt{2500-1056.25}\\ y =\sqrt{1443} \approx 37.99

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.

<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>

8 0
3 years ago
Someone please help with my math on my page!!!
kumpel [21]

I'll try! What's the link?

6 0
3 years ago
Can someone please help me on this?
zalisa [80]
The slope issssss 2
5 0
3 years ago
Read 2 more answers
Write the repeating decimal as a fraction.<br>0.1872 ​
Gekata [30.6K]
117/625 is the fraction
7 0
3 years ago
Read 2 more answers
Other questions:
  • I don't not understand this please help!!!!!
    8·1 answer
  • Use the distributive property to rewrite -3 (5 - b) =
    14·2 answers
  • A picture that measures 8 cm by 6 cm is to be surrounded by a mat. The mat is to
    13·1 answer
  • 1.Refer to the system of linear equations shown below. Which of the following statements gives the best choice for multiplying t
    5·1 answer
  • In the figure show AD CE abd FB intersect at point F
    6·1 answer
  • . A football team outscored its opponents 5:3. If the opponents scored 12 points, how many points did
    15·1 answer
  • CAN SOMEONEE PLEASEEE HELL MEEEEEE I will give BRAINLEST !!!
    6·1 answer
  • What is the image point of (9,5) after a translation right 4 units and up 4<br> units?
    8·1 answer
  • Pleaseeee helpppp now I have 2 minutes
    12·2 answers
  • Need help please !!!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!