1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonja [21]
3 years ago
15

The length of a rectangular floor is twice its width. The floor is partially covered by a rectangular carpet whose length is the

same as the length of the floor and whose width is 2 feet less than the width of the floor. If the area of the carpet is 160 square feet, what is the length, in feet, of the floor?\
Mathematics
1 answer:
NISA [10]3 years ago
8 0

Answer:

20ft

Step-by-step explanation:

We have two unknowns, the length and the width of the floor. Let us represent this by l and w respectively.

Firstly, we are told that the length of the floor is twice its width. This mathematically means that l = 2w

The width of the rectangular carpet is 2ft less than the width of the floor but the floor length is equal. This means that the width of the floor is (w - 2)ft

Now we are told that the area of the rectangular carpet is 160 sq.ft

This means the length of the carpet multiplied by the width is 160

Mathematically:

l * (w-2) = 160

We know that l = 2w, if we substitute this:

2w(w - 2) = 160

w(w -2) = 80

w^2 -2w = 80

w^2 - 2w - 80 = 0

w^2 -10w + 8w -80 = 0

w(w -10) + 8(w - 10) = 0

(w + 8)(w -10) = 0

w = -8 or 10

Since distance cannot be negative, we ignore the -8 and use the 10 only

Hence the width is 10ft

The length is 2 times the width. The length is thus 2 * 10ft = 20ft

You might be interested in
If you help me with these problems I will give you a brainlist and be your friend :) but only if you help me get it right!.
brilliants [131]
C. 1700 is the correct answer.
4 0
3 years ago
Read 2 more answers
(2x - 1) ft<br> (x + 4) ft<br> 7 ft
anygoal [31]
What is the question?
7 0
3 years ago
I need help with all those problems please
Klio2033 [76]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ 2. a: Associative property  b: Associative property  c: Associative property

d: Associative property

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

8 0
3 years ago
If the perimeter of the rectangle is 6x+c what is the value of c
nikdorinn [45]
C is 2*length I hope
5 0
3 years ago
Rearrange the equation so m is the independent variable.<br> -2m-5n=7m-3n<br> n=___
Aneli [31]
<h2>Answer:</h2>

The equation is given by:

        n=\dfrac{-9}{2}m

<h2>Step-by-step explanation:</h2>

We are given a equation in terms of the variable m and variable n as follows:

-2m-5n=7m-3n

Now, we are asked to find the equation in terms of m i.e. we have to consider m as independent variable and n as dependent variable since it's value is to be expressed in terms of m.

Now, we add 5n on both the sides of the equation to get:

-2m=7m-3n+5n\\\\i.e.\\\\-2m=7m+2n

Now, we subtract 7m from both the sides of the equation to get:

-2m-7n=2n\\\\i.e.\\\\2n=-9m\\\\n=\dfrac{-9}{2}m

3 0
3 years ago
Other questions:
  • Help its geometry pleaseeee​
    5·1 answer
  • Express 8.5454545454... as a rational number, in the form p/q where p and q are positive integers with no common factors.
    8·1 answer
  • X^2+2x in factored form
    6·1 answer
  • The velocity function, in feet per second, is given for a particle moving along a straight line. Find (a) the displacement and (
    5·1 answer
  • Given the system<br><br> y &gt; -2<br><br> x + y &lt; 4
    13·1 answer
  • HELP ASAP!!simplify the following<br>(-8z)^2
    14·1 answer
  • 1. The measure of angle AOB is 56 degrees. What is the measure of angle ACB?
    15·1 answer
  • The diameter of a sphere with a volume of 12,348 cubic ft is ___ ft.
    11·1 answer
  • For which data set would the median be a better measure of center than the mean?
    11·1 answer
  • Pls help i will reward crown to the first person who is right!!!!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!