Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
For the first one:
m is the slope, or how much the line goes up compared to goes right. In this case, the line goes up 40 every time it goes right 10. We write this as a fraction so 40/10, which simplifies to 4. Therefore the equation would be y = 4x.
(x – h)² + (y – k)²<span> = r</span>²
Fill in the numbers
(x – 7)²<span> + (y +3)</span>²<span> = 49</span>
um 600?? I'm sorry if that's wrong
You figure out the amount of chocolate doughnuts sold by multiplying 2/3 by 7 1/4
first you change 7 1/4 to an improper fraction:
7 1/4= 29/4
now multiply 2/3×29/4 by multiplying the two numerators then putting that over the two denominators multiplied: (2×29)/(3×4)=58/12
now simplify:58/12=4 10/12= 4 5/6
the answer is Stanley's doughnut shop sold
4 5/6 trays of chocolate doughnuts