For a polygon with 10 sides, which equation below represents the sum of the interior angles in the polygon?

Write the relation as a set of ordered pairs.

AveGali [126]

Answer:

Is B (-2,-1),(0,0),(2,1)

Step-by-step explanation:

x y

-2 -1

0 0

2 1

I think!!??

5 0

3 years ago

HELP ME <br> I WILL GIVE YOU BRAINLIEST

lana66690 [7]

76, because the graph shows how many visitors there are around 90 degrees

3 0

3 years ago

What is the median of those in the the picture please help

Molodets [167]

Answer:

Median is 24.5

Step-by-step explanation:

Median is the middle number in a set of numbers. If we have two middle numbers, we get the average. And from the question, listing them out, we have this

0,1, 2, 3,4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49.

The middle number here is 24 and 25. Getting their average will be 24.5

5 0

3 years ago

A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and

natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: $E=k\frac{q}{r^{2} }$ ; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: $p=\frac{q}{A}$ ; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: $S=4\pi r^{2}$ ; which gives us the surface of a sphere.

The inner surface: $Si=4\pi (0.06m)^{2} = 0.04 m^{2}$

The outer surface: $S=4\pi (0.08m)^{2}=0.08m^{2}$

Now we can calculate the charges,

Inner charge: $Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC$

Outer charge: $Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC$

Then, we are able to calculate both fields:

Inner field: $Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}$

Outer field: $Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}$

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0

3 years ago

What is the answer??????

dexar [7]

Answer:

38 5/28

Step-by-step explanation:

Well start with the whole numbers 24 and 13 This is adding so that means everything has to be added together. 13+24=37 Now, lets go the fractions.

Find the LCD (Least Common Denominator) of 3/4 and 3/7 and rewrite to solve with the equivalent fractions. (remember the Denominator is the BOTTOM PART of the Fraction. Such as the 4 in 3/4.)

LCD = 28

21/28 + 12/28 = 33/28 which can be simplified to 1 5/28. Combining the whole and fraction parts 37 + 1 + 5/28 = 38 5/28 And that will be your answer. Another way you can do this is

converting mixed numbers to fractions Meaning put them in improper form where the numerator (the top number of a fraction is bigger than the denominator such as 4/3) , our initial equation becomes, 99/4 + 94/7

Applying the fractions formula for addition,

(99×7) + (94×4) / 4×7

= 693+376 / 28 =

= 1069/ 28

Simplifying 1069/28, the answer is

= 38 5/28

And one more thing. An easier way to make a mixed number a improper fraction is the multiply the denominator by the whole number then add the numerator and whatever the denominator is it stays for example

38 5/28.

28 times 38 = 1064 then add the 5 and you get 1069! But we aren't done yet, the denominator was 28 so that means the full answer is 1069/28 and that is the Improper fraction form!

Hope this helps! (sorry I took so long)

~R.C aka dj

6 0

3 years ago