Answer:
I really also need the answer
Step-by-step explanation:
You can use many methods but the way I do it is just multiply it out and you get 215,865
Blue will bend most because it's the farthest on the rainbow. And red will bend least due to it being at the beginning of the rainbow.
Answer: did you ever get the answer?
Step-by-step explanation:
Answer:
![W \le 6](https://tex.z-dn.net/?f=W%20%5Cle%206)
Step-by-step explanation:
Given
![Area = 60ft^2\ (max)](https://tex.z-dn.net/?f=Area%20%3D%2060ft%5E2%5C%20%28max%29)
![Length = 10ft](https://tex.z-dn.net/?f=Length%20%3D%2010ft)
Required
Represent the width as an inequality
First, we represent the area as an inequality.
![Area = 60ft^2\ (max)](https://tex.z-dn.net/?f=Area%20%3D%2060ft%5E2%5C%20%28max%29)
max as used above means less than or equal to.
So, we have:
![Area \le 60](https://tex.z-dn.net/?f=Area%20%5Cle%2060)
The area of a rectangle is:
![Area = L * W](https://tex.z-dn.net/?f=Area%20%3D%20L%20%2A%20W)
So, we have:
![L * W \le 60](https://tex.z-dn.net/?f=L%20%2A%20W%20%5Cle%2060)
Substitute 10 for L
![10 * W \le 60](https://tex.z-dn.net/?f=10%20%2A%20W%20%5Cle%2060)
Divide both sides by 10
![\frac{10 * W}{10} \le \frac{60}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B10%20%2A%20W%7D%7B10%7D%20%5Cle%20%5Cfrac%7B60%7D%7B10%7D)
![W \le \frac{60}{10}](https://tex.z-dn.net/?f=W%20%5Cle%20%5Cfrac%7B60%7D%7B10%7D)
![W \le 6](https://tex.z-dn.net/?f=W%20%5Cle%206)