Brent wants to make a frame for a painting. The painting is square and has area 144 square inches. The framing material costs
$1.10 per inch. How much will he spend? You may assume that the framing material Brent buys will be the exact amount he needs.
2 answers:
Answer:
52.80
Step-by-step explanation:
We can determine the side length of the painting
A = s^2 for a square painting
144 = s^2
Taking the square root of each side
sqrt(144) = sqrt(s^2)
12 = s
We need to find the perimeter for the painting
For a square painting
P =4s
P = 4*12
P = 48
Multiplying by the cost per inch
1.10 * 48 =52.8
Answer:
$52.80
Step-by-step explanation:
Area = side²
144 = side²
side = 12 in
Perimeter = 4 × side
= 4 × 12 = 48 in
Cost = 48 × 1.10
= 52.80
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<u>Question # 1:</u>
Given that:
![\displaystyle \frac{p+10}{2} = 16\\\\Multiply\ both\ sides\ by \ 2]]\\ p+10 = 2 \times 16\\\\p+10 = 32\\\\Subtract \ 10\ to \ both \ sides\\\\p = 32-10\\\\p = 22](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bp%2B10%7D%7B2%7D%20%3D%2016%5C%5C%5C%5CMultiply%5C%20both%5C%20sides%5C%20by%20%5C%202%5D%5D%5C%5C%20p%2B10%20%3D%202%20%5Ctimes%2016%5C%5C%5C%5Cp%2B10%20%3D%2032%5C%5C%5C%5CSubtract%20%5C%2010%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cp%20%3D%2032-10%5C%5C%5C%5Cp%20%3D%2022)
<u>Question # 2:</u>
Given that:
![\displaystyle \frac{z+12}{2} = 10\\\\Multiply \ both \ sides \ by \ 2\\\\z+12 = 10 \times 2\\\\z+12 = 20\\\\Subtract \ 12\ to \ both \ sides\\\\z = 20-12\\\\z = 8\\\\\rule[224]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bz%2B12%7D%7B2%7D%20%3D%2010%5C%5C%5C%5CMultiply%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%202%5C%5C%5C%5Cz%2B12%20%3D%2010%20%5Ctimes%202%5C%5C%5C%5Cz%2B12%20%3D%2020%5C%5C%5C%5CSubtract%20%5C%2012%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cz%20%3D%2020-12%5C%5C%5C%5Cz%20%3D%208%5C%5C%5C%5C%5Crule%5B224%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
The equation is 
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