Question

In a certain year, the population of Smallburg was $4{,}000.$ In the following year, the population increased by $15\%.$ What was the resulting population?

Answer 1

Answer:

4,600

Step-by-step explanation:

To solve this problem, we need to multiply add 15% of 4,000 back to 4,000.

First, change 15% into a decimal:

15% -> $\frac{15}{100}$ -> 0.15

Next, multiply 4,000 by 0.15:

$x= 4,000(0.15)$

$x=600$

The last step is to add the 600 back to 4,000:

$4,000 + 600 = 4,600$

The population of Smallburg the following year was 4,600.