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kipiarov [429]
3 years ago
14

#4: Which property could be used to solve the equation below? *15 = x + 13​

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

Step-by-step explanation:

Steps to solve:

15 = x + 13

~Subtract 13 to both sides

2 = x

Best of Luck! :D

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(solve) i dont get it
Artist 52 [7]
I think the answer is x=10
8 0
3 years ago
A coffee shop serves three times as many cups of regular coffee as decaffeinated coffee. If the shop serves d cups of decaffeina
galben [10]

Answer:

Number of cups of regular coffee the shop sells = 3d

Step-by-step explanation:

Let

d = cups of decaffeinated coffee

Three times as many cups of regular coffee as decaffeinated coffee.

Number of cups of regular coffee the shop sells = 3d

8 0
3 years ago
Jalen inherited a collection of vintage comic books. An appraiser separated the comic
sladkih [1.3K]

Jalen has total 63 comic books.

Step-by-step explanation:

Given,

Total value of comic books = $3135

Let,

Number of $45 comic books = x

Number of $65 comic books = y

According to given statement;

45x+65y=3135     Eqn 1

x=y+33                  Eqn 2

Putting value of x from Eqn 2 in Eqn 1

45(y+33)+65y=3135\\45y+1485+65y=3135\\110y=3135-1485\\110y=1650\\

Dividing both sides by 110

\frac{110y}{110}=\frac{1650}{110}\\y=15

Putting y=15 in Eqn 2

x=15+33\\x=48

Total comic books = x+y

Total comic books = 48+15 = 63

Jalen has total 63 comic books.

Keywords: addition, elimination method

Learn more about elimination method at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

7 0
3 years ago
ASAP
mr Goodwill [35]

Answer: A

Step-by-step explanation:

8 0
2 years ago
Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
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