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Ede4ka [16]
3 years ago
8

Solve. 2x+4 3 b. x 1/3 d. x< 1/3

Mathematics
1 answer:
tangare [24]3 years ago
6 0

Answer:

Step-by-step explanation:

LOL I WHICH I COULD SOLVE THAT

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A regular octagon with side length a cm can be made by cutting off
Ksivusya [100]

Answer:

one side = \frac{a\sqrt{2}}{2}

Step-by-step explanation:

if you draw an octagon on a piece of paper, you can draw a square around it, you should be able to see a diagram of this attached, ignore the 6.

Let's say TP = a

since it's a regular octagon, TP = HT

and using the Pythagoras Theorem,  we know a² + b² = c² and thus:

√(AT² + HA²) = HT

and since AT = HA which we will call x, the equation becomes:

√(2x²) = HT = a

rearrange the equation to solve for x and you get:

2x² = a²

x² = \frac{a^{2} }{2}

x = \frac{a}{\sqrt{2}}

which, if you rationalise the denominator, you get:

x = \frac{a\sqrt{2}}{2}

5 0
3 years ago
Help pls..................
Triss [41]

Answer:

Area = 152ft²

Step-by-step explanation:

Simpifly:

A = 13(13-6) + 9(13-6)

A = 13(7) + 9(7)

A = 22(7)

A = 22(7)

A = 20(7)+2(7)

A = 140 + 14

A = 152

5 0
2 years ago
Classify the quadrilateral by selecting its most specific name.
Lemur [1.5K]
Rectangle definitely not a parallelogram
7 0
3 years ago
A sandwich store charges $20 to have three turkey subs delivered and $26 to have four delivered. How much does the store charge
sweet [91]
$6 per turkey and $2 delivery fee. Do da math.
7 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi

Let us find first and second derivative for f(x)

f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in (0, \pi/2) U(\pi,3\pi/2)\\

and decreasing in (\pi/2, \pi)U(3\pi/2,2\pi)

x=\frac{\pi}{4}, \frac{3\pi}{4}

f"(\pi/4)

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = 2sin \pi/4+2cos \pi/4 =2\sqrt{2}

Minimum value = 2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}

c)

f"(x) =0 gives tanx =-1

x= 3\pi/4, 7\pi/4

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

3 0
3 years ago
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