Answer:
x = 5 and x = -19
Step-by-step explanation:
You're on the right track. It's the "discriminant" that tells you what you want to know here. Before starting, arrange the terms of your quadratic in descending orders of x: 5x^2 + 14x - 19 = 0 (Note that I assumed you meant 14x instead of just 14).
Then the coefficients of this quadratic are a = 5, b = 14 and c = -19.
You are referring to the "quadratic formula." It states this:
-b ± √(b²-4ac)
x = -----------------------
2a
So, we insert the a, b and c values as indicated above:
-14 ± √( 14² - 4[5][-19] ) -14 ± √(196 - 4[5][-19] ) -14 ± √576
x = ----------------------------------- = ---------------------------------- = ----------------------
2(10) 20 20
This comes out to:
x = (-14 + 24) / 2 and x = (-14 - 24) / 2
or:
x = 5 and x = -19
A factor is one part of a product.
In the given expression first we separate the terms.
here we have two terms: 15 and 20x
factors of first term 15 : since just one number is there so factors of 15 would be 1, 3, 5 and 15
factors of second term 20x: product of 20 and x gives 20x, so factors of 20x are 1,2,4,5, 10,20 and x
Answer:
Whats the
Step-by-step explanation:
*combine like terms*
-6v-24=2v+8
*add 24 to both sides*
-6v-24+24= 2v+8+24
*simplify*
-6v=2v+32
*subtract 2v from both sides*
-6v-2v=2v+32-2v
*simplify*
-8v=32
*divide both sides by -8*
-8v/-8= 32/-8
ANSWER: v=-4
